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QveST [7]
3 years ago
8

Find one value of r that is a solution to the equation: (x - 2)^2 – 6(x - 2) + 5 = 0 x=?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
Verify the following identity’s.
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Log3 (x squared + 7x + 21) = 2
Nezavi [6.7K]

Step-by-step explanation:

log <base a> b = x

means

a^x = b

So

3^2 = x^2+7x+21

x^2 + 7x + 21 - 9 = 0

x^2 + 7x + 12 = 0

(x+3)(x+4)

x = -3 or -4

3 0
3 years ago
Please help!!!!<br> Thank you!
Rudik [331]

Answer:

option 3, 900 square units

Step-by-step explanation:

area=20*(32+13)

=900

7 0
3 years ago
Read 2 more answers
Help me please 10 ////////////////
madam [21]

Answer:

part A is 120

Step-by-step explanation:

6 × 20 = 120

part B

3 0
3 years ago
Read 2 more answers
P(An B) = 2/3
Gala2k [10]

Answer:

8/9

Step-by-step explanation:

p(A/B) = p(A inersect B) / p(B)

3 0
3 years ago
What is the probability that the mean duration of the 24 rowers with idna exceeds 63 minutes?
statuscvo [17]

Answer:

Step-by-step explanation:

Given that: Training-session duration of female rowers with normal iron status is Normally distributed, with mean 69 minutes and standard deviation 18minutes.

Solution:

z score shows the relationship between sample means. The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by the formula:

z=\frac{x-\mu}{\sigma}\\\\for\ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }  \\\\where\ \mu=mean,\sigma=standard\ deviation,x=raw\ score

Given that μ = 69 minutes, σ = 18 minutes, n = 24

For x > 63 minutes:

z=\frac{x-\mu}{\sigma / \sqrt{n} } =\frac{63-69}{18/\sqrt{24} }=-1.63

From the distribution table, P(x > 63) = P(z > -1.63) = 1 - P(z < 1.63) = 1 - 0.0516 = 0.9484

7 0
3 years ago
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