Answer:
The answers are explained below.
Explanation:
a.) * and + has same priority so then: ((a * b) - (1+c))
b.) For (++c++) = ((++c)++) , prefix has high precedence.
In remaining operators * and mod has same precedence So evaluate from left to right. ((a * (b - 1)) / (((++c)++) mod d))
There for order of evaluation: ((a * (b - 1)) / (((++c)++) mod d))
c.) for (d * e / a - 3), * has high priority so ((d *e) / a - 3). Now / and - have same priority so then see association from left to right. so
And & has more priority than / so then order of evaluation: ((a - b) / (c & (((d * e) / a) - 3))
d.) In question d, unary minus(-) has high priority then, - has high priority, then and has high priority and then or has low priority. So then order of evaluation: ((-a) or ((c = d) and e))
e.) Here > and <= has high and same precedence then ( a > b) xor c or (d <= 17)
now xor and or has same priority so associates from left to right.
order of evaluation is : ( ((a > b) xor c) or (d <= 17))
f.) uniary minus(-) has high precedence than + so order of evaluation is : ((-a) + b)
Rewriting the expression where there are no precedence rues and the statement is given right to left associativity:
a. c + 1 - b * a
b. d mod (++c++) / (1 - b) * b
c. (3 - a / e * d) & c / (b - a)
d. e and d = c or -a
e. 17 <= d or c xor b > a
f. b + -a
