JL is a common tangent to circles M and K at point J. If angle MLK measures 61ᵒ, what is the length of radius MJ? Round to the n
earest hundredth. (Hint: Show that triangles LMJ and LKJ are right triangles, and then use right triangle trigonometry to solving for missing sides of the right triangles.)
In the problem of insufficient data quantities. I can get a general solution.We know that tangent to a circle is perpendicular to the radius at the point of tangency. It's mean that triangles LJM and LJK are rights.
Let angle JLK like X.
So, angle JLM=61-x.
And it's mean that by using right triangle trigonometry
Cindy buys 18 more stickers in the start. This results in 13+18= 31 stickers. She then gets five for her birthday. 31+5=36 so she now has 36 stickers but she then gives eight away which means she has 36-8=28 stickers. She uses ten stickers to decorate so Cindy has 28-10=18 stickers left
The slope of the line is calculated using y2 - y1 / x2 - x1 Substituting the given values -8 - 27 / 5 - 0 = -7 The rate of change or the slope is -7 And the initial value is the value of y when x is 0. From the first coordinates, the initial value is 27.
