We have been given that a particular type of cell increases by 75% in number every hour. We are asked to find the number of cells present at the end of 12 hours if there are initially 4 of these cells.
We will use exponential growth formula to solve our given problem.
, where,
y = Final amount,
a = Initial amount,
r = Growth rate in decimal form,
x = Time.
Upon substituting initial value 
and 
in above formula, we will get:
Therefore, there will be approximately 3300 cells at the end of 12 hours.
3 triangles! Give brainliest please!
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2
Answer:
Option C
Step-by-step explanation:
According to the graph, there are vertical asymptotes at 
and 
. Therefore, C is correct because -3+3=0 and 7-7=0.
