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Leviafan [203]
2 years ago
14

7. Factor by grouping.

Mathematics
1 answer:
hjlf2 years ago
6 0

Answer:

Step-by-step explanation: 4

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3 over 32 simplified?
Bess [88]
It is already simplified, three goes into three once but three cant go into 32 without there being a remainder.
7 0
3 years ago
A coin is tossed 6 times. what is the probability that the number of heads obtained will be 2? express your answer as a fraction
Valentin [98]
For this you will have to make a tree diagram
it will be so much easier although there is a way to do it

probability of getting heads is = 1/2 there for 10 tosses its (1/20)^10

4 0
3 years ago
Help please WILL GIVE BRAINLIEST TO RIGHT ANSWER!​
Tcecarenko [31]

Answer:

I think A is the answer

but D is the correct answer "kunno"

Step-by-step explanation:

hope it helps :)

4 0
3 years ago
Read 2 more answers
Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symm
klemol [59]
y = \frac{3}{x^{2} - 4} + 1

Domain: x² - 4 ≠ 0
                 + 4 + 4
                    x² ≠ 4
                 √x² ≠ √4
                    x ≠ ±2
           x ≠ -2 and x ≠ 2
     (-∞, -2) ∨ (-2, 2) ∨ (2, ∞)

Range: y ≠ 1
    (-∞, 1) ∨ (1, ∞)

Intervals: Increasing: (0.25 , ∞)
              Decreasing: (-∞, 0.25)

Symmetry: X-axis: Not Symmetric
                  Y-axis: Not Symmetric
                  Origin: Not Symmteric

Extrema: Maximum Relative: x = 0
                Minimum Relative: Nothing
3 0
2 years ago
a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m
lesya [120]

Answer:

62.5 \:in^2

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism=x^2l

Since l=5 Inches

5x^2=31.25\\x^2=6.25\\x=2.5\: Inches

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area=2(x^2+xl+xl)=2(x^2+2xl)

=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2

Therefore, 62.5 \:in^2 of cardboard is needed,

4 0
2 years ago
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