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Rama09 [41]
3 years ago
12

Explain the difference between the average rate of change of y as x changes from a to b, and the instantaneous rate of change of

y at x=a.
A. The average rate of change of y as x changes from a to b can be found using the formula ​, where y​f(x). The instantaneous rate of change of y at xa is found by taking the limit as b approaches a of the stated formula.
B. The average rate of change of y as x changes from a to b can be found by using the formula ​, where y​f(x). The instantaneous rate of change of y at xa is found by taking the limit as b approaches a of the stated formula.
C. The instantaneous rate of change of y at xa can be found by using the formula ​, where y​f(x). The average rate of change of y as x changes from a to b is found by taking the limit as b approaches a of the stated formula.
D. The instantaneous rate of change of y at xa can be found using the formula ​, where y​f(x). The average rate of change of y as x changes from a to b is found by taking the limit as b approaches a of the stated formula.

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0

The given options are not clear enough, so i have attached the full question with the correct options.

Answer:

Option A:

Average rate of change=[f(b) - f(a)]/(b-a)

Instantaneous rate of change of y at x = a is found by finding the limit as "b" approaches "a"

Step-by-step explanation:

The average rate of change of a function f(x) on an interval [a, b] is defined as the slope of the secant line, which is calculated by the formula;

[f(b) - f(a)]/(b - a)

While the instantaneous rate of change of f(x) at x = a is defined as the slope of the tangent line, which is calculated by finding the limit as "b" approaches "a". This is written as; f'(a) .

Looking at the options, the correct answer is option A.

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Answer:

The number of houses built in Town B is 56.

Step-by-step explanation:

We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.

Also, 70 houses were built in Town A during 210.

Let the number of houses built in Town B be 'x'.

So, according to the question;

Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B

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Answer:

B.  \:  \boxed{66.8}

Step-by-step explanation:

to \: solve \: this \: little \: poblem : we \:apply \: the \: pythagrean \: rule \to \\  \boxed{SOH} \boxed{CAH} \boxed{TOA} \to \\ we \: are \: been \: given :  \to \\ the \:  \boxed{opp }\: of \: the \: required \: angle \:  = 35. \\ the \:  \boxed{adj }\: of \: the \: required \: angle \:  = 15. \\  now \: lets \: apply \: \boxed{TOA}\to \: \tan( \theta)  =  \frac{opp}{adj}   \to\\  \tan( \theta)  =  \frac{opp}{adj}  =  \frac{35}{15}  = 2.3333333333 \\  \theta =  \tan {}^{ - 1} (2.3333333333)  \\   \boxed{\theta = 66.80}

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