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Bezzdna [24]
2 years ago
15

The length of a rectangle is 5 cm less than twice the width. The perimeter of the rectangle is 80 cm. Find the dimensions

Mathematics
1 answer:
balandron [24]2 years ago
6 0

Answer:

W=16 2/3

L=28 1/3

Step-by-step explanation:

L=2W-5

80=2W+2L

80=2W+2(2W-5)

80=2W+4W-20

80=6W-20

100=6W

W=16 2/3

L=2(16 2/3)-5

L=33 1/3 -5

L=28 1/3

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Answer:

144cm²

Step-by-step explanation:

Area of square A Aa = La²

Area of square B  Ab= Lb²

If the length of each side of square B is 4cm greater than the length of each side of square A, then;

Lb =  La + 4 ... 1

Also if the area of square B is 70cm² greater than the area of square A, then;

Ab = Aa + 70

Since Aa =  La² and Ab =  Lb²

Lb² = La² + 70 ...2

Substitute 1 into 2;

(La+4)² = La²+70

Expand

La²+8La+16 = La²+80

8La+16 = 80

8La = 80 - 16

8La = 64

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La = 8cm

Since Lb = La + 4

Lb = 8 + 4

Lb = 12cm

Area of square B = Lb²

Area of square B = 12²

Area of square B = 144cm²

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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