Y=x^2-6x+14
=x^2-6x+9-9+14
x^2-3x-3x+9 +5
x(x-3)-3(x-3)+5
(x-3)^2+5
here h=3
minimum value would be 5
Answer:
Full answer is in the media.Good luck.
Answer:
Step-by-step explanation:
In the two independent samples application, it involves the test of hypothesis that is the difference in population means, μ1 - μ2. The null hypothesis is always that there is no difference between groups with respect to means.
Null hypothesis: ∪₁ = ∪₂. where ∪₁ represent the mean of sample 1 and ∪₂ represent the mean of sample 2.
A researcher can hypothesize that the first mean is larger than the second (H1: μ1 > μ2 ), that the first mean is smaller than the second (H1: μ1 < μ2 ), or that the means are different (H1: μ1 ≠ μ2 ). These ae the alternative hypothesis.
Thus for the z test:
if n₁ > 30 and n₂ > 30
z = X₁ - X₂ / {Sp[√(1/n₁ + 1/n₂)]}
where Sp is √{ [(n₁-1)s₁² + (n₂-1)s₂²] / (n₁+n₂-2)}
Answer:
12
Step-by-step explanation:
4y - 2x
= 4(7) - 2(8)
= 28 - 16
= 12
Answer:
D
Step-by-step explanation:
A) more like parallel line
B) That is angle bisecting
C) Neither Angle or line bisector
