the area of the green square is 21% greater than the area of the yellow square l. workout the ratio a:b

Mathematics

1 answer:

gogolik [260]3 years ago

3 0

Answer:

11:10

Step-by-step explanation:

Let area of yellow square be x

Area of green square=x+0.21*x=1.21*x

Ration of side=(1.21x)^(1/2)/(x)^(1/2)=1.1=11/10.

Answered by Gauthmath

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Do I need to put parentheses in this? Why it why not?

Oksana_A [137]

Answer:

Parentheses can change the result of the answer. If you want to add 4 and 0.95 first, then multiply that number by 3, then you need parentheses.

Step-by-step explanation:

When you are given the question 3 X 4 + 0.95, it has to types of operations. People solve using the order PEDMAS:

Parentheses,

Exponents,

Division and Multiplication,

Addition and Subtraction.

Since there are no parentheses or exponents, the solver will do multiplication first, then addition.

3 X 4 + 0.95 Multiply first

= 12 + 0.95 Now add

= 12.95 Answer without parentheses

If you add parentheses around 4 + 0.95, the answer would change. According to PEDMAS, the parentheses must be solved before anything else.

3 X (4 + 0.95) Add inside parentheses

= 3 X (4.95) Now multiply

= 14.85 Answer with parentheses

If you added parentheses around 3 X 4, the answer would not change, because you still multiply first.

(3 X 4) + 0.95 Solving parentheses first

= 12 + 0.95 Add

= 12.95 Answer same as original

3 0

3 years ago

Help please!! i don’t understand this one!

12345 [234]

Answer:

C, D

Step-by-step explanation:

This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.

For ax² +bx +c = 0, the solutions are ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the given equation, a=2, b=11, c=5, so this becomes ...

$x=\dfrac{-11\pm\sqrt{11^2-4\cdot2\cdot5}}{2\cdot2}=\dfrac{-11\pm\sqrt{81}}{4}\\\\x=\dfrac{-11\pm9}{4}=\left\{-\dfrac{20}{4},-\dfrac{2}{4}\right\}=\{-5,-\frac{1}{2}\}$

The solutions are ...

C. x = -5

D. x = -1/2

_____

My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.