Answer:
a = -86.
Step-by-step explanation:
By the Factor Theorem, if x + 4 is a factor then P(-4) = 0, so:
P(-4) = 2(-4)^3 - 11(-4)^2 + a(-4)- 40 = 0
-128 - 176 - 4a - 40 = 0
-4a = 128 +176 + 40
-4a = 344
a = -86.
Answer: 198 is your answer:65+66+67 = 198 Hope I helped!
Step-by-step explanation:
There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
To learn more about students visit:
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Answer:
33.33%
Step-by-step explanation:
We need to calculate the <u>unit selling price and cost of each cosmetics.</u>
If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;
x = 1 cosmetic
since 360 = 12 cosmetic
cross multiply
12x = 360
x = 360/12
x = 30
Hence the unit cost price of the cosmetics will be Rs. 30
Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)
Selling price per unit = Rs. 40
Cost price per unit = Rs. 30
percent gain = SP-CP/CP * 100%
percent gain = 40-30/30 * 100
percent gain = 10/30 * 100
percent gain = 100/3
percent gain = 33.33%
Hence the percentage gain is 33.33%
