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3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

Otrada [13]3 years ago

4 0

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What is another way to say 14 over 16 in fractions ( preferably in lowest number example 4 over 8 equals 1 over 2 both are halve

Degger [83]

Answer:

7/8

Step-by-step explanation:

The greatest common factor in each is two so you divide both the numerator and the denominator by two to simplify the fraction

4 0

3 years ago

Express the fraction in simplest form.

blagie [28]

4/16 in simplest form:

First, we need to find the greatest common factor (GCF) of 4 and 16. Why? We have to find the number that we are going to be dividing the numerator and denominator by to get the simplest form of the fraction. Let's list the factors for 4 and 16:

Factors of 4: 1, 2, 4
Factors of 16: 1, 2, 4, 8, 16

Out of the two sets of factors, which ones are the common ones? The common factors between the two are 1, 2, and 4. Since we are looking for the GREATEST common factor, we have to look at the highest number out of 1, 2, and 4. The GCF is 4, since 4 is higher than 1 and 2.

Second, we now have a number that we are going to divide the numerator and denominator by, which is 4. The numerator is the top number of the fraction (4) and the denominator is the bottom number of the fraction (16).Let's divide now.

$4 \div 4 = 1 \\ 16 \div 4 = 4$

Third, we now have the simplified fraction. (1) is our new numerator, and (4) is our new denominator. This makes the new simplified fraction 1/4. So, your answer is C.

Answer in fraction form: $\fbox {1/4}$
Answer in decimal form: $\fbox {0.25}$

4 0

3 years ago

Read 2 more answers

Prove-: sin5A = 5cos^4 A sinA - 10cos^2 A sin^3 A + sin^5 A

jeyben [28]

$A=x\\\\sin5x=5cos^4xsinx-10cos^2xsin^3x+sin^5x\\\\L=sin(3x+2x)=sin3xcos2x+sin2xcos3x=(*)\\-------------------------------\\sin3x=sin(2x+x)=sin2xcosx+sinxcos2x\\=2sinxcosxcosx+sinx(cos^2x-sin^2x)\\=2sinxcos^2x+sinxcos^2x-sin^3x=3sinxcos^2x-sin^3x\\-------------------------------$

$sin3xcos2x=(3sinxcos^2x-sin^3x)(cos^2x-sin^2x)\\=3sinxcos^4x-3sin^3xcos^2x-sin^3xcos^2x+sin^5x\\=3sinxcos^4x-4sin^3xcos^2x+sin^5x\\-------------------------------$

$cos3x=cos(2x+x)=cos2xcosx-sin2xsinx\\=cosx(cos^2x-sin^2x)-2sinxcosxsinx\\=cos^3x-sin^2xcosx-2sin^2xcosx=cos^3x-3sin^2xcosx\\-------------------------------$

$sin2xcos3x=2sinxcosx(cos^3x-3sin^2xcosx)\\=2sinxcos^4x-6sin^3xcos^2x\\-------------------------------$

$
(*)=3sinxcos^4x-4sin^3xcos^2x+sin^5x+2sinxcos^4x-6sin^3xcos^2x\\\\=5sinxcos^4x-10sin^3xcos^2x+sin^5x=R$

$=======================================\\\\sin(\alpha+\beta)=sin\alpha cos\beta+sin\beta cos\alpha\\\\cos(\alpha+\beta)=cos\alpha cos\beta-sin\alpha sin\beta\\\\sin2\alpha=2sin\alpha cos\alpha\\\\cos\alpha=cos^2\alpha-sin^2\alpha$

5 0

3 years ago

What is 67,456 divided by 32 and tell me how

V125BC [204]

Answer:

2108

Step-by-step explanation:

Divide 67,456 by 32, using long division.

1) How many times 32 go into 67? (2 times, with a remainder of 3)

2) Bring down the 4.

3) How many times does 32 go into 34? (1 time, with a remainder of 2)

4) Bring down the 5

5) How many times does 32 go into 25? (0 times, so write 0)

6) Bring down the 6.

7) How many times does 32 go into 256? ( 8 times, no remainder)

8) Your answer is 2108

4 0

3 years ago

What is the area of a rectangle with a length of 9 and a width of 17?

ikadub [295]

Answer:

153 units squared

Step-by-step explanation:

To solve, multiply your length by your width.

$A=lw\\A=9(17)\\A=153$

5 0

4 years ago

Read 2 more answers