Answer:
A) sin θ = 3/5
B) tan θ = 3/4
C) csc θ = 5/3
D) sec θ = 5/4
E) cot θ = 4/3
Step-by-step explanation:
We are told that cos θ = 4/5
That θ is the acute angle of a right angle triangle.
To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.
Now, the identity cos θ means adjacent/hypotenuse.
Thus, adjacent side = 4
Hypotenuse = 5
Using pythagoras theorem, we can find the third side which is called opposite;
Opposite = √(5² - 4²)
Opposite = √(25 - 16)
Opposite = √9
Opposite = 3
A) sin θ
Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;
sin θ = 3/5
B) tan θ
Trigonometric ratio for tan θ is opposite/adjacent. Thus;
tan θ = 3/4
C) csc θ
Trigonometric ratio for csc θ is 1/sin θ. Thus;
csc θ = 1/(3/5)
csc θ = 5/3
D) sec θ
Trigonometric ratio for sec θ is 1/cos θ. Thus;
sec θ = 1/(4/5)
sec θ = 5/4
E) cot θ
Trigonometric ratio for cot θ is 1/tan θ. Thus;
cot θ = 1/(3/4)
cot θ = 4/3
The numbers are 59 and 61
<span>0=2x+3(3x-4)-(-x+14)
Follow BEDMAS
</span><span>0=2x+9x-12-(-x+14)
</span>0=2x+9x-12+x-14
Add like terms
0=11x-12+x-14
0=12x-12-14
0=12x-26
Flip the eqaution
12x-26=0
Move -26 across the equal sign
12x=0+26
12x=26
x=26/12
x=13/6
Hope this helps! A thanks/brainiest answer would be appreciated :)
The answer is 15%
Explanation:
Team A has 42 members and team b has 18 more than team A so team b has 60 members. In order for the teams to be equal, there’d need to be 51 people on each team(60+42/2=51). There are 9 extra people on team b, so we need 9/60 , divide and you get 15%.
Answer:
Both equation represent functions
Step-by-step explanation:
The function is the relation that for each input, there is only one output.
A. Consider the equation
This equation represents the function, because for each input value x, there is exactly one output value y.
To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.
When you intersect the graph of the function with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.
B. Consider the equation
This equation represents the function, because for each input value x, there is exactly one output value y.
When you intersect the graph of the function with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.
