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3 years ago

What is the area of a rectangle with a length of 9 and a width of 17?

Mathematics

2 answers:

ikadub [295]3 years ago

5 0

Answer:

153 units squared

Step-by-step explanation:

To solve, multiply your length by your width.

$A=lw\\A=9(17)\\A=153$

alexdok [17]3 years ago

5 0

Answer:

A=153

Step-by-step explanation:

The area of a rectangle with a length of 9 and a width of 17 is 153.

Formula: A=wl

A=wl=17·9=153

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The city of Raleigh has 9500 registered voters. There are two candidates for city

kotykmax [81]

Answer:

Population = All registered voters in Raleigh city

Population size = 9500

Sample size = 360

Proportion of sample statistic for brown = 0.3167

3008 voters

Step-by-step explanation:

Population refers to all elements which meets the requirement for a specific experiment or research interest.

Number of voters for brown = 114

Number of voters for Feliz = 210

Undecided = 36

Sample statistic for proportion in support of brown :

Proportion = x / n

x = number who said they'll vote for brown

n = sample size

Sample statistic for proportion in support of brown = 114 / 360 = 0.3167

Using the proportion ; number from population who'll vote brown :

Sample proportion * population size

0.3167 * 9500 = 3008 voters

3 0

3 years ago

Someone please help plz

yaroslaw [1]

Answer: 14

Step-by-step explanation:

12^2+8^2=208 square root is 14

4 0

3 years ago

Read 2 more answers

Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A

lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let $n(A)$ the number of elements in A.

Remember, the number of elements in $A_1 \cup A_2 \cup A_3$ satisfies

$n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)$

Then,

a) If $A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200$ , and if $A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000$

Since $A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1$

$n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600$

b) Since the sets are pairwise disjoint

$n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200$

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

$n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193$

8 0

3 years ago

Amir buys a new car for £16470. The value of the car will depreciate by 2% each year. Work out how much amir's car will cost aft

Ronch [10]

Answer:

Amir's car will cost £10348.88 after 23 years.

Step-by-step explanation:

I finally found a UK human!

This is compound interest so you have to find a decimal multiplier and multiply that with £16470 to the power of 23.

The decimal multiplier would be 0.98. This is because you do 100% - 2% as depreciating basically means a decrease, which gives you 98% and then you divide that by 100 to get your decimal multiplier - 0.98.

16470 × $0.98^{23}$ = £10348.88

I hope that helps you!! ^-^

7 0

3 years ago

P=13 z=4

hram777 [196]

Answer:

you have more outfits than your friend

Step-by-step explanation:

you:

5*13=65outfits

friend:

4*9=36outfits

3 0

3 years ago