If ( x - 1 ) * ( x + 3 ) = 0 => x = 1 or x = -3;
But, (x-1)(x+3)=1 => x^2 + 3x -x - 3 = 1 => x^2 + 2x - 4 = 0;the discriminant is 2^2 - 4 * 1 * ( -4 ) = 20 => the solutions are x1 =
( - 2 +
) / 2 ; x2 = - 2 -
) / 2;
In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.
It would be 7 with 75 over 100....it would look like 7 75/100. then simplify it.
Use the formula for area of a triangle:
Area = 1/2 x base x height.
Fill in what you know:
40 = 1/2 x 20 x height
Multiply both sides by 2:
80 = 20 x height
Divide both sides by 20
Height = 4 m
The answer will be p = i/rt instead. You just flipped the process by mistake :)
