Step-by-step explanation:
subtract-13 from -13 get zero
then, subtract 13 from 77 =64
then do divide 15 from 15
then divide 15 from 64 = 4.26 repeat
Answer:
y = one-half x + three-fourths
Step-by-step explanation:
The 2-point form of the equation of a line can be used for starters.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values
y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little
y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...
y = 1/2x -4/20 +19/20
y = 1/2x +15/20
y = 1/2x +3/4 . . . . line in slope-intercept form
Answer:
Sin theta = 12/13
Step-by-step explanation:
From the question;
Cot theta = 5/12
Kindly recall;
Cot theta = 1/ tan theta
Hence, tan theta = 12/5
Mathematically
tan theta= opposite/adjacent
to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides
let hypotenuse be h
h^2 = 12^2 + 5^2
h^2 = 144 + 25
h^2 = 169
h = √169
h = 13
But sine theta = opposite/ hypotenuse = 12/13
Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
Attached the solution with work shown.
