Answer:
A = 3
B = 1
C = 2
D = 10
E = 2
F = Not listed
G = 1
Step-by-step explanation:
![\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B270x%5E5y%5E7%7D%20%3D%5Csqrt%5B3%5D%7B27%2A10x%5E5y%5E7%7D%3D3xy%5E2%5Csqrt%5B3%5D%7B10x%5E2y%7D)
For this case, we have that the equation of the position is given by:

To find the velocity, we must derive the equation from the position.
We have then:

Then, we evaluate the derivative for time t = 8.
We have then:
Answer:
the instantaneous velocity at t = 8 is:
Answer:
f(x) = 4x² + 9x - 28
Step-by-step explanation:
Create the polynomial by multiplying (4x - 7) and (x + 4) together:
f(x) = 4x² + 16x - 7x - 28, or
f(x) = 4x² + 9x - 28
Next time, please share the given answer choices. Thanks.
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