15/14 lies between which two numbers please Also send write answer
1 answer:
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1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
2.
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
2.
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
Graph of the inequality 3y-2x>-18 is given below.
Step-by-step explanation:
We are given the inequality, 3y-2x>-18
Now, using the 'Zero Test', which states that,
After substituting the point (0,0) in the inequality, if the result is true, then the solution region is towards the origin. If the result is false, then the solution region is away from the origin'.
So, after substituting (0,0) in 3y-2x>-18, we get,
3\times 0-2\times 0>-18
i.e. 0 > -18, which is true.
Thus, the solution region is towards the origin.
Hence, the graph of the inequality 3y-2x>-18 is given below.
Let the women's height be AE and distance between the women and tower be AC.
Also let the height of tower be BC.
Now, clearly it is forming a triangle.
So, in triangle ABC,
Hence, BC = 59.5m
So, BD(total height of the tower)
Therefore, total height of the tower =
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Hope it helps you:)
