Question

Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x?

Answer 1

Step-by-step explanation:

Step 1:  Subtract 4x from both sides

$2x^2 - 4x = 4x - 4x - 7$

$2x^2 - 4x = -7$

Step 2:  Add 7 to both sides

$2x^2 - 4x + 7 = -7 + 7$

$2x^2 - 4x + 7 = 0$

Step 3:  Use the Quadratic Formula

$x = \frac{ -b \pm \sqrt{b^2 -4ac} }{2a}$

$x = \frac{ -(-4) \pm \sqrt{(-4)^2 - 4(2)(7)} }{ 2(2 )}$

$x = \frac{ 4 \pm \sqrt{-40} }{4}$

$x = \frac{4 \pm2i \sqrt{10} }{4}$

$x = \frac{2 \pm i\sqrt{10}}{2}$

Answer:  $x = \frac{2 \pm i\sqrt{10}}{2}$

Answer 2

You have to make sure you follow this step by step