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4 years ago

25 pealties decreased by 35% is how many penalties

2 answers:

7 0

35% of 25 penalties are:
25 penalties* (32/100)= 8 penalties

25 penalties -8 penalties= 17 penalties.

The final answer is 17 penalties~

Harman [31]4 years ago

5 0

16.25 penalties.
35% of 25 is 8.75.
25-8.75=16.25

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Melinda has $22 and plans to save $10 each week. George has $10 and plans to save $13 each week.

Dimas [21]

Lets say Y is the amount they will save.
So Melinda's savings could be described by the equation Y=22+10X, where X is the number of weeks. The same goes to George, but his equation would be Y=10+13X.

To save the same amount, their equations must match:
22+10X = 10+13X
Solving this, one gets
12 = 3x
=> 4=x
So the answer is 4 weeks.

3 0

4 years ago

Read 2 more answers

The product of two numbers is 192. what is the minimum value of the sum of the first value plus twice the second value

VARVARA [1.3K]

Let x and y be the two positive numbers. - Their product is 192: x * y = 192 equation 1

- the sum of the first plus twice the second is a minimum: x + 2y

From the first equation, y = 192 / x.
Substitute that into the second equation:

x + 2y = x + 2(192/x ) = x + 384/x

f(x) is minimum when f'(x) = 0 and f"(x) > 0

f(x)= x + 384/x

f(x) = 1-384/x^2

1-384 / x^2 = 0

x^2-384 = 0

x^ 2= 354
x = radical 354 = 18.8 here i'm confused why the number is decimal
???/

4 0

4 years ago

A soda bottling plant fills cans labeled to contain 12 ounces of soda. The filling machine varies and does not fill each can wit

AnnZ [28]

Answer:

$12.1-1.64\frac{0.35}{\sqrt{50}}=12.019$

$12.1+1.64\frac{0.35}{\sqrt{50}}=12.181$

So on this case the 90% confidence interval would be given by (12.019;12.181)

And we can conclude at 90% of confidence that the true mean is between (12.019, 12.181) and since the lower limit is higher than 12 we can conclude that the specification is not satisfied

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=12.1$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=0.35$ represent the population standard deviation

n=50 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$

Now we have everything in order to replace into formula (1):

$12.1-1.64\frac{0.35}{\sqrt{50}}=12.019$

$12.1+1.64\frac{0.35}{\sqrt{50}}=12.181$

So on this case the 90% confidence interval would be given by (12.019;12.181)

And we can conclude at 90% of confidence that the true mean is between (12.019, 12.181) and since the lower limit is higher than 12 we can conclude that the specification is not satisfied

8 0

3 years ago

Which point is not a solution to this graphed inequality?

Leya [2.2K]

Answer:

B. (-4, -3)

Step-by-step explanation:

If we graph the points onto the graph, you can see that (-4, -3) is not in the solution set shown in the graph. In order to be a solution in the set, the solution has to be graphed above the dotted line; it has to be in the shaded region.

7 0

3 years ago

Read 2 more answers

What is the solution set of the equation using the quadratic formula? x2+6x+10=0 {−3+2i,−3−2i} {−6+2i,−6−2i} {−3+i,−3−i} {−2i,−4

olga2289 [7]

Answer:

The solution set of the quadratic function $x^{2}+6\cdot x +10$ is $\{-3+i,-3-i\}$ .