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tresset_1 [31]
3 years ago
6

How many different ways can a family visit Philadelphia, Baltimore, and Washington?

Mathematics
2 answers:
uysha [10]3 years ago
5 0
Philadelphia Baltimore Washington
Philadelphia Washington Baltimore
Baltimore Philadelphia Washington
Baltimore Washington Philadelphia
Washington Baltimore Philadelphia
Washington Philadelphia Baltimore

Six different ways
jek_recluse [69]3 years ago
4 0

The mathematic way would be 3! = 6


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What is x2+5x+6 <br> ?????
mina [271]

Answer:

try A!

Step-by-step explanation:

8 0
3 years ago
How do you know a radical expression is in simplest form?
Diano4ka-milaya [45]
Answer: To know whether a radical expression is in simplest form or not you should put the numbers and letters inside the radical in terms of prime factors. Then, the radical expression is in the simplest form if all the numbers and letters inside the radical are prime factors with a power less than the index of the radical

Explanation:

Any prime factor raised to a power greater than the index of the root can be simplified and any factor raised to a power less than the index of the root cannot be simplified

For example simplify the following radical in its simplest form:


\sqrt[5]{3645 a^8b^7c^3}

1) Factor 3645 in its prime factors: 3645 = 3^6 * 5

2) Since the powr of 3 is 6, and  6 can be divided by the index of the root, 5, you can simplify in this way:

- 6 ÷ 5 = 1 with reminder 1, so 3^1 leaves the radical and 3^1 stays in the radical

3) since the factor 5 has power 1 it can not leave the radical

4) the power of a is 8, then:

8 ÷ 5 = 1 with reminder 3 => a^1 leaves the radical and a^3 stays inside the radical.

5) the power of b is 7, then:

7 ÷ 5 = 1 with reminder 2 => b^1 leaves the radical and b^2 stays inside the radical

6) the power of c is 3. Since 3 is less than 5 (the index of the radical) c^3 stays inside the radical.

7) the expression simplified to its simplest form is

3ab \sqrt[5]{3.5.a^3b^2c^3}

And you know it cannot be further simplified because all the numbers and letters inside the radical are prime factors with a power less than the index of the radical.
7 0
3 years ago
Read 2 more answers
10) Gabe put up a fence around his rectangular vegetable garden this weekend.
dybincka [34]

Answer:

The length is 16 ft, and the width is 3 ft.

Step-by-step explanation:

Let L = length & let W = width.

The perimeter of a rectangle is

P = 2(L + W)

The area of a rectangle is

A = LW

We know the perimeter and the area, so we substitute those values int he equations above and we switch sides in both equations.

Perimeter: 2(L + W) = 38

Divide both sides by 2:

L + W = 19

Area: LW = 48

We have a system of two equations in two unknowns:

L + W = 19

LW = 48

Solve the first equation for L and substitute it into the second equation.

L = 19 - W

(19 - W)W = 48

19W - W^2 - 48 = 0

Multiply both sides by -1, and rearrange the order of the terms.

W^2 - 19W + 48 = 0

(W - 16)(W - 3) = 0

W - 16 = 0 or W - 3 = 0

W = 16 or W = 3

Use W = 3 to find L

L = 19 - W

L = 19 - 3

L = 16

Answer: The length is 16 ft, and the width is 3 ft.

3 0
3 years ago
Need help ASAP please!
zmey [24]

Answer:

(mark me brainliest) q=5

Step-by-step explanation:

q would be = 5

and so would the height = 5

here is the rule for 45-90-45

hypotenuse is basically the other two lengths with \sqrt{2}

so that is why q would be 5

7 0
3 years ago
Solve y=-1/4x+2<br> 2x+8y=-40
PolarNik [594]

Answer:

No solution

Step-by-step explanation:

This is just a simple system of equations.

y=-1/4x+2

8y+2x=-40

Get the same variables onto their corresponding sides, so it will look like this:

y=-1/4x+2

8y=-2x-40

Now here, you have to be careful, because to solve for the system of equations, you need to make sure you are multiplying the equation proportionately.

8y=-2x+16

8y=-2x+40.

But here you see that they share the same variables in a similar format, but their values are supposed to be different, meaning that this equation is a false claim. So you would respond to the question as "no solution.

5 0
3 years ago
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