Answer:
Step-by-step explanation:
The identities you need here are:
and 
You also need to know that
x = rcosθ and
y = rsinθ
to get this done.
We have
r = 6 sin θ
Let's first multiply both sides by r (you'll always begin these this way; you'll see why in a second):
r² = 6r sin θ
Now let's replace r² with what it's equal to:
x² + y² = 6r sin θ
Now let's replace r sin θ with what it's equal to:
x² + y² = 6y
That looks like the beginnings of a circle. Let's get everything on one side because I have a feeling we will be completing the square on this:

Complete the square on the y-terms by taking half its linear term, squaring it and adding it to both sides.
The y linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 in on both sides:

In the process of completing the square, we created within that set of parenthesis a perfect square binomial:

And there's your circle! Third choice down is the one you want.
Fun, huh?
-2 x=10
-2 x/-2=10/-2
x=-5
Or
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
radius = √98
center = (5.9,6.7)
equation of the circle = ?
Step 02:
Equation of the circle
(x - a) ² + (y - b) ² = r ²
(a , b) = center
(x - 5.9) ² + (y - 6.7) ² = (√98) ²
(x - 5.9) ² + (y - 6.7) ² = 98
The answer is:
(x - 5.9) ² + (y - 6.7) ² = 98
Answer:
i need them
Step-by-step explanation:
Answer:
(3, 1 )
Step-by-step explanation:
Given the 2 equations
y = - x + 4 → (1)
y = x - 2 → (2)
Substitute y = x - 2 into (1)
x - 2 = - x + 4 ( add x to both sides )
2x - 2 = 4 ( add 2 to both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Substitute x = 3 into either of the 2 equations and solve for y
Substituting into (2)
y = 3 - 2 = 1
solution is (3, 1 )