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Angelina_Jolie [31]
3 years ago
9

A jogger goes 1.5km west and then turns south.If the jogger finishes 1.7 km from the starting point,how far south did the jogger

go?
Mathematics
1 answer:
kakasveta [241]3 years ago
6 0
Hello!

You can use the Pythagorean Theorem to solve this

a^{2} + b^{2} = c^{2}

c is the hypotenuse
a and b are the legs

Put in the values you know

1.5^{2} + b^{2} = 1.7^{2}

Square the numbers

2.25+ b^{2} =2.89

Subtract 2.25 from both sides

b^{2} =0.64

Take the square root of both sides

b = 0.8

The answer is 0.8km

Hope this helps!
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Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


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Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


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We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


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Second root

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Third root

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Fifth and Sixth roots

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7 0
3 years ago
Will GIVE BRAINLIEst
snow_lady [41]

Answer:

answer will be an=3n+11

Step-by-step explanation:

because when we substitute them...it make sense.

<em>the</em><em> </em><em>rule</em><em> </em><em>is</em><em> </em><em>an</em><em>=</em><em>3</em><em>n</em><em>+</em><em>1</em><em>1</em>

<em>lets</em><em> </em><em>substitute</em><em>:</em>

<em>(</em><em>i</em><em>)</em><em>.</em><em>1</em><em>4</em><em>=</em><em>3</em><em>(</em><em>1</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>(</em><em>ii</em><em>)</em><em>1</em><em>7</em><em>=</em><em>3</em><em>(</em><em>2</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>(</em><em>iii</em><em>)</em><em>2</em><em>0</em><em>=</em><em>3</em><em>(</em><em>3</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>(</em><em>iv</em><em>)</em><em>2</em><em>3</em><em>=</em><em>3</em><em>(</em><em>4</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>it</em><em> </em><em>does</em><em> </em><em>make</em><em> </em><em>sense</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>I hope it will help u</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
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