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3 years ago

5c-20<15c+10 solve inequality

1 answer:

7 0

Combine all like terms and use inequality as = sign

5c-20 <15c + 10
Add 20 to each side

5c< 15c + 30

Subtract 15c from each side

-10c < 30

Divide each side by -10

c < -3

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How many ten thousands in 420189

zaharov [31]

There are 20 ten thousands

5 0

3 years ago

What 2 numbers multiply to get -120 and add to get -14

mr Goodwill [35]

Answer:

-20 and 6

Step-by-step explanation:

-20 x 6 = -120

and if you add -20 and 6, you get -14.

5 0

3 years ago

Rewrite in simplest terms: -10(-3m-10)-3(-8m+3) i don't usually ask questions that often but I actually need help this time. so

andreev551 [17]

Answer:

The simplest form is 6m+91.

Step-by-step explanation:

Consider the given information.

$-10(-3m-10)-3(-8m+3)$

First, remove the parenthesis by multiplying -10 and -3 inside the parenthesis.

$30m+100-24m-9$

Now, rearrange the like terms.

$30m-24m+100-9$

Combine the like terms.

$6m+91$

Hence, the simplest form is 6m+91.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%

victus00 [196]

Let

$\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}$

The exponent is indeed $2n-1$ - not a typo!

Take the antiderivative of $f$ , denoted by $F$ . This recovers a factor of $2n$ in the denominator, which lets us condense it to a single factorial.

$\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}$

Recall the series expansion of sine,

$\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}$

Then with a little algebraic manipulation, we get

$\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x$

Differentiate to recover $f$ .

$f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}$

Finally, $f(\pi) = \frac1\pi$ , so our sum is

$\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}$

3 0

1 year ago

Odd numbers greater than 4 written in roster notation

klemol [59]

Answer:

Step-by-step explanation:

{5,7,9,11,13,15,17,19,21}

It goes on infinitely unless I did this wrong, if I did sorry:c

6 0

3 years ago