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Sphinxa [80]
3 years ago
6

Matthew has 7 basketball cards, 8 baseball cards, and 9 football cards. If Matthew wants to separate the cards into two equal pi

les, how many cards will be in each pile?
Mathematics
2 answers:
just olya [345]3 years ago
8 0
7 + 8 + 9 = 24

24 / 2 = 12

So 12 cards in each pile.
Semenov [28]3 years ago
8 0
\dfrac{7+8+9}{2}=\dfrac{24}{2}=\boxed{12}
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Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe
kramer
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that<span> a is a rational number and b be an irrational number, A, C, D, and F are true statements.</span>
4 0
3 years ago
Can y’all help me on question 40?!
Anastaziya [24]

Answer:

t = 3c

Step-by-step explanation:

3 0
2 years ago
Given the figure above, determine​
Ad libitum [116K]

Answer:

what is it I didn't understand sorry

4 0
2 years ago
HELP PLZ!!!! How did you do 2a-5b? And what are the answers
Xelga [282]

both of the questions?

3 0
3 years ago
Find the missing term (need help)
katen-ka-za [31]

Answer:

x² - 10x + 34

Step-by-step explanation:

given the roots are x = 5 ± 3i then the factors are

(x - (5 + 3i))(x - (5 - 3i))

= (x - 5)² - 9i² ← expand (x - 5)²

= x² - 10 x + 25 + 9 → [ i² = - 1 ]

= x² - 10x + 34

the missing term is 10x



7 0
3 years ago
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