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vlabodo [156]
3 years ago
14

What is 1(z) when z = -7/12

Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0
It will just be -7/12 because anything times 1 stays the same
UkoKoshka [18]3 years ago
6 0
The answer will be -7/12. Hope it help!
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PLEASE HELP ME WITH THIS I FINSIH MY QUARTER TONIGHT FOR SCHOOL AND I NEED TO GET THIS DONE!! Austin and his children went to th
astra-53 [7]

Answer:

1a+2p=14\\a+p=9\\\\a=4\\p=5

Step-by-step explanation:

1a+2p=14\\a+p=9\\\\a+p=9\\a=9-p\\\\1(9-p)+2p=14\\9-p+2p=14\\9+p=14\\p=5\\\\a=9-(5)\\a=4

Graphing:

Slope intercept form y=mx+b

a is y, p is x

y=-2x+14

y=-x+9

Intercept at (5,4)

8 0
3 years ago
*PLEASE ANSWER, I NEED HELP I DONT GET IT*
7nadin3 [17]

Answer:

the third graph

Step-by-step explanation:

2x<6/÷2 we get x<3

3x+2>-4

3x>-4-2

3x>-6/÷3

x>-2

5 0
3 years ago
Read 2 more answers
Carson took a total of 24 quizzes over the course of 4 weeks. How many weeks of school will Carson have to attend this quarter b
erastovalidia [21]

Answer:

9 weeks

Step-by-step explanation:

Assuming he takes equal number of quizzes weekly then having taken 24 quizzes within 4 weeks means for every week Carson took 24/4=6 quizzes per week.

With a target of 54 quizzes this quater and while maintaining 6 quizzes per week then Carson will take 54/6= 9 weeks to meet thw target.

Therefore, Carson needs 9 weeks this quater

7 0
4 years ago
Please help me ASAP!Please this is due soon and i don't have all day.
Helga [31]

<u><em>Answer:</em></u>

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

<u><em>Explanation:</em></u>

<u>The formula to calculate the percent change in mass is given as:</u>

PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100

<u>1- Section 1:</u>

Old mass = 7.83 g and New mass = 8.268 g

PercentChange = \frac{8.268-7.83}{7.83}*100 =5.59%

<u>2- Section 2:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.4}*100 =-2.16%

<u>3- Section 3:</u>

Old mass = 7.3 g and New mass = 6.51 g

PercentChange = \frac{6.51-7.3}{7.3}*100 =-10.82%

<u>4- Section 4:</u>

Old mass = 7.49 g and New mass = 7.0 g

PercentChange = \frac{7.0-7.49}{7.49}*100 =-6.54%

<u>5- Section 5:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.7.4}*100 =-2.16%

<u>6- Section 6:</u>

Old mass = 7.89 g and New mass = 8.51 g

PercentChange = \frac{8.51-7.89}{7.89}*100 =7.86%

Hope this helps :)

6 0
3 years ago
a hiker in africa discovers a skull that contains 41% of its original amount of c-14. find the age of the skull to the nearest y
DochEvi [55]

9514 1404 393

Answer:

  7371 years

Step-by-step explanation:

The half-life of Carbon-14 is reportedly about 5730 years. Then the exponential decay equation can be written as ...

  f = (1/2)^(t/5730)

where f is the fraction remaining after t years.

Taking logarithms and solving for t, we find ...

  log(f) = (t/5730)log(1/2)

  t = 5730·log(f)/log(1/2)

For the fraction f = 0.41, the age is approximately ...

  t = 5730·log(0.41)/log(1/2) ≈ 5730·1.286304 ≈ 7371 . . . years

The age of the skull could be estimated to be 7371 years.

5 0
3 years ago
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