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STatiana [176]
3 years ago
13

The fuel economy of a car, measured in miles per gallon, is modeled by the function ƒ(s) = –0.009s2 + 0.699s + 12 where s repres

ents the speed of the car, measured in miles per hour. What's the fuel economy of the car when it travels at an average of 20 miles an hour?
Mathematics
2 answers:
notsponge [240]3 years ago
8 0

Answer:

22.38 miles per gallon is the fuel economy of the car.

Step-by-step explanation:

The fuel economy of the car is modeled by the function f(s) = -0.009s² + 0.699s + 12

Where s = speed of the car measured in miles per hour.

Now we have to find the fuel economy of the car when it travels at an average of 20 miles an hour.

Now we plug in the value of s = 20 miles per hour in the given function

f(20) = -0.009(20)² + 0.699(20) + 12

       = -3.6 + 13.98 + 12

       = 22.38 miles per gallon

Therefore, at the speed of 20 miles and hour fuel economy of the car will be 22.38 miles per gallon.

valina [46]3 years ago
7 0

25.62= -.009(20*2)+ .699(20)+12


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the answer would be -2

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3 years ago
A pan of lasagna cut into 100 servings is equally shared among a group of people. For Exercises
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53).  100 servings / 20 people  =  (100/20) (svngs/ppl)

                                                 = 5 servings per person.

         Each person gets 1/20 = 5% = 0.05 of the pan.


54).  100 servings / 40 people  =  (100/40) (svngs/ppl)

                                                 = 2.5 servings per person.

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55).  100 servings / 30 people  =  (100/30) (svngs/ppl) 

                                                  = (3 and 1/3) servings per person.

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3 0
3 years ago
A country's population in 1991 was 114 million. In 1997 it was 120 million. Estimate the population in 2014 using exponential gr
Rufina [12.5K]
The answer is 138 million.

Step 1. Calculate the growth rate.
Step 2. Calculate the population number in 2014.

We will use the formula for exponential growth:
A = P * eⁿˣ
where:
A - the final amount (value)
P - the initial amount (value)
e - the mathematical constant (e ≈ 2.72)
n - the growth rate
x - the time

Step 1:
A = 120 million = 120 000 000
P = 114 million = 114 000 000
n = ?
x = 1997 - 1991 = 6
Therefore:
120 000 000 = 114 000 000 * e ^{n*6} \\ e ^{n*6} =120 000 000 /114000000 \\ e ^{n*6} =1.05 \\
Logarithm both sides of the equation:
ln(e ^{n*6})=ln(1.05) \\ n*6*ln(e) = ln(1.05) \\ 6n=ln(1.05) \\ n = \frac{ln(1.05)}{6} \\ n = \frac{0.05}{6} \\ n = 0.0083

Step 2:
Now when we know the growth rate, it is easy to estimate the population in 2014
A = ?
P = 120 000 000
n = 0.0083
t = 2014 - 1997 = 17
A = 120 000 000 * e ^{0.0083*17}  \\ &#10;A = 120 000 000 * e^{0.1411}   \\ &#10;A = 120 000 000 * 1.15 \\ &#10;A = 138 000 000&#10;
Thus, the population will be 138 million in 2014

8 0
3 years ago
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