3 years ago

How to find the maximum height projectile motion?

1 answer:

7 0

Y=v(initial)*t+1/2at^2
since the velocity is zero at the maximum height then we get
y=1/2at^2
a is just acceleration due to gravity so a=g which is 9.8 m/s^2.
so y=1/2gt^2.

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Let C be between D and E. Solve for x DC = 5x + 8 CE = 3x + 5 DE = 61

morpeh [17]

DE/2 = 30.5
CE=30.5
DC=30.5

3x + 5 = 30.5
3x = 30.5 - 5
3x = 25.5
25.5/3 =8.5
x=8.5

8 0

3 years ago

Drag a statement or reason to each box to complete this proof. If 4x+5=17, then x=3.

natita [175]

Statement Reason

1) 4x + 5 = 17 Given

2) 4x + 5 - 5 = 17 - 5 Subtraction property of equality

3) 4x = 12 Simplifying

4) 4x/4 = 12/4 Division property of equality

5) x = 3 Simplifying

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3 years ago

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tamaranim1 [39]

13=2c+5
-5 -5
8=2c
/2 /2
4=c
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| c=4 |
|____|

3 0

3 years ago

39. The diagram shows Luciana and Tanner's location

AlexFokin [52]

Answer:

2<d<8

Step-by-step explanation:

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3 years ago

Which equation justifies why nine to the one third power equals the cube root of nine?

AVprozaik [17]

Answer:

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

Step-by-step explanation:

we know that

The Power of a Power Property , states that :To find a power of a power, multiply the exponents

$(a^{b})^{c}=a^{b*c}$

In this problem we have

$9^{\frac{1}{3}} =\sqrt[3]{9}$

Remember that

$\sqrt[3]{9}=9^{\frac{1}{3}}$

Raise to the third power

$[9^{\frac{1}{3}}]^3$

Applying the power of power property

$9^{\frac{3}{3}}$

$9^{1}$

$9$

therefore

nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine

8 0

3 years ago

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