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Reptile [31]
3 years ago
7

What is the solution to the equation1 over the square root of 8 = 4(m − 2)? (1 point)

Mathematics
1 answer:
kupik [55]3 years ago
6 0
Rationalize the denominator, divide by 4, add 2.
\dfrac{1}{\sqrt{8}}=4(m-2)\\\\ \sqrt{\dfrac{2}{16}}=4(m-2)\\\\ \dfrac{\sqrt{2}}{4\cdot 4}=m-2\\\\ m=2+\dfrac{\sqrt{2}}{16}
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Answer:

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Step-by-step explanation:

In a triangle Δ ABC, AC = 7, and BC = 18.

Therefore, the length of the third side of the triangle Δ ABC i.e. length of AB can have a maximum value of < (7 + 18) i.e. 25 and the minimum value of the length AB will be > (18 - 7) i.e. 11

Hence, the length of AB will be given by 25 > AB > 11.

Now, AB = AD + DB = 6 + DB {Since length of AD is given to be 6}

Therefore, 25 > 6 + DB > 11

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