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ahrayia [7]
3 years ago
8

Which graph represents the function f(x)=−3x+7

Mathematics
1 answer:
zepelin [54]3 years ago
4 0

It's be a line that crosses the y-axis at (0,7) and has a slope of -3 or -3/1.

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Factor the expression using the GCF.<br> 22 + 11 =
Maurinko [17]
Answer should be 22= 11x2 11= 11x1, something like that :)
5 0
3 years ago
Q.16 please<br> With steps
blsea [12.9K]

The equations

2x^2+9x-5=0

and

2\left(t-\dfrac12\right)^2+9\left(t-\dfrac12\right)-5=0

are really the same, we're just setting x=t-\dfrac12, or t=x+\dfrac12.

2x^2+9x-5=(2x-1)(x+5)=0\implies x=\dfrac12,x=-5

So we get

t=\dfrac12+\dfrac12=1,t=-5+\dfrac12=-\dfrac92

8 0
3 years ago
Today the temperature is 0 degrees Fahrenheit. The temperature rose
VladimirAG [237]

Answer: -11 degrees Fahrenheit

Step-by-step explanation:

3 0
3 years ago
See question in image and show workings​<br><br>Note : 1 nautical mile = 1.86km
ycow [4]

Answer:

a)

AB is on the latitude 30°N.

<u>Find AB:</u>

  • AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km

BC is along longitude 35°W

<u>Find BC:</u>

  • BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km

<u>Total distance traveled:</u>

  • 6482.15 + 5585.77 = 12067.92 km

<u>Convert the distance to nautical miles:</u>

12067.92/1.86 = 6488.13 nautical miles

b)

<u>Find the average speed:</u>

  • 6488.13/22 = 294.92 nautical miles / hour

<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>

3 0
2 years ago
g A trial jury of 6 people is selected from 20 people: 8 women and 12 men. What is the probability that the jury will have an od
cricket20 [7]

Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

Number of men = 12

Number of women = 8

Number of jury to be selected = 6

For the jury to have an odd number of women. it must have either of the three.

1. 1 woman , 5 men

2. 3 women, 3 men

3. 5 women, 1 man

The total possible ways of selecting the 6 people jury is;

N = 20C6 = 20!/6!(20-6)!

N = 38760

The possible ways of selecting;

Case 1 : 1 woman, 5 men

N1 = 8C1 × 12C5

N1 = 8 × 792 = 6336

Case 2 : 3 women , 3 men

N2 = 8C3 × 12C3

N2 = 12320

Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

6 0
3 years ago
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