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seraphim [82]
3 years ago
15

A truck passes point A on a straight level road with a constant velocity of 12 m/s. At the same instant, an automobile starts fr

om rest at point A and travels in the same direction as the truck with a constant acceleration of 1.8 m/s2. How long a time does the automobile take to pass the truck from the instant it starts at point A?
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

t = 13.3 s

Explanation:

Let the car will overtake the truck after time "t" seconds

so here we can say that after time "t" seconds the distance covered by the car will be same as that of distance covered by truck

So we have

d_{car} = d_{truck}

so we have

d_{truck} = 12 t

d_{car} = \frac{1}{2}(1.8 m/s^2) t^2

so now we have

12 t = 0.9 t^2

t = 13.3 s

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Two objects are dropped from a bridge, an interval of 1.00 s apart. What is their separation 1.00 s after the second object is r
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<em>171.5m</em>

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A 24.7-g bullet is fired from a rifle. It takes 2.73 × 10-3 s for the bullet to travel the length of the barrel, and it exits th
Gala2k [10]

Answer:

F_a_v_g=7093333.33N*s

Explanation:

The impulse or average force in classical mechanics is the variation in the linear momentum that a physical object experiences in a closed system. It is defined by the following equation:

F_a_v_g=m*\frac{\Delta v}{\Delta t}=m*\frac{v_2-v_1}{t_2-t_1}

Where:

m=mass\hspace{3}of\hspace{3}the\hspace{3}object

v_2=final\hspace{3}velocity\hspace{3}of\hspace{3}the\hspace{3}object\hspace{3}at\hspace{3}the\hspace{3}end\hspace{3}of\hspace{3}the\hspace{3}time\hspace{3}interval

v_1=initial\hspace{3}velocity\hspace{3}of\hspace{3}the\hspace{3}object\hspace{3}when\hspace{3}the\hspace{3}time\hspace{3}interval\hspace{3}begins.

t_2=final\hspace{3}time

t_1=initial\hspace{3}time

Asumming v1=0 and t1=0:

F_a_v_g=m* \frac{v_2}{t_2} =(24.7)*\frac{784}{2.73*10^{*3} } =7093333.333N*s

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