$22,102 is invested, part at 11% and the rest at 7%. If the interest earned from the amount invested at 11% exceeds the interest

Question

3 years ago

12

$22,102 is invested, part at 11% and the rest at 7%. If the interest earned from the amount invested at 11% exceeds the interest

earned from the amount invested at 7% by $913.46, how much is invested at each rate? (Round to two decimal places if necessary.)

Mathematics

1 answer:

Yuliya22 [10] · Answer 1 · 2022-05-22T12:34:09+03:00

X + y = 22,102
.11x = .07y + 913.46 = x= (7/11)y + 8304.18

((7/11)y + 8304.18) + y = 22,102

(18/11)y = <span>13797.82
</span>
y= 13797.82/(18/11)

y=8432.00

8,432.00 dollars are invested at 7%
13,670.00 dollars are invested at 11%

Check
.07 x 8432= 590.24
.11 x 13,670 = 1503.70

1503.70 - 590.24 = 913.46