Answer:
p(x) = 0.6x³ - 200x² + 500x- 300
Step-by-step explanation:
Given the cost function and revenue function as:
C(x) = 500x² + 100x
R(x) = -0.6x³ + 700x² – 400x + 300
To get the profit function:
p(x) = C(x) - R(x)
p(x) = 500x² + 100x -(-0.6x³ + 700x² – 400x + 300)
open the parenthesis
p(x) = 500x² + 100x + 0.6x³ - 700x² + 400x - 300
p(x) = + 0.6x³+500x² - 700x² + 100x+ 400x- 300
p(x) = 0.6x³ - 200x² + 500x- 300
Hence the profit function is expressed as p(x) = 0.6x³ - 200x² + 500x- 300
Answer:
in 4/5 fraction of the game they scored two or more runs.
I think it is D
Hope my answer help you?
C(a,b), because the x-coordinate( first coordinate) is a (seeing as it is situated directly above point B, which also has an x-coordinate of a) and the y-coordinate ( second coordinate) is b (seeing as it is situated on the same horizontal level as point D, which also has a y-coordinate of b)
the length of AC can be calculated with the theorem of Pythagoras:
length AB = a - 0 = a
length BC = b - 0 = b
seeing as the length of AC is the longest, it can be calculated by the following formula:
It is called "Pythagoras' Theorem" and can be written in one short equation:
a^2 + b^2 = c^2 (^ means to the power of by the way)
in this case, A and B are lengths AB and BC, so lenght AC can be calculated as the following:
a^2 + b^2 = (length AC)^2
length AC = √(a^2 + b^2)
Extra information: Seeing as the shape of the drawn lines is a rectangle, lines AC and BD have to be the same length, so BD is also √(a^2 + b^2). But that is also stated in the assignment!
