Question

A running track in the shape of an oval is shown. The ends of the track form semicircles. A running track is shown. The left and right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 62 m and length of one straight edge 100 m What is the perimeter of the inside of the track? (π = 3.14)

Answer 1

Two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.
Length = 140 m ; Width = 68 m
Circumference of a circle = 2 π r circumference of a cirlce =  2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52
length = 2 * 140 m = 280 m
perimeter of the oval = 213.52 m + 280 m = 493.52 m

Answer 2

two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.

Length = 140 m ; Width = 68 m

Circumference of a circle = 2 π r

circumference of a cirlce =  2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52

length = 2 * 140 m = 280 m

perimeter of the oval = 213.52 m + 280 m = 493.52 m