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GrogVix [38]
3 years ago
11

I need help so someone plz give me the steps and answer and graph it so i can understand how to solve these types of problems ag

ain?
+ 6 = 4/5 ( + 3)

3a. Identify the slope of the equation.

3b. Identify the point used in the equation.

3c. Graph the equation.

Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0
Y + 6 = 4/5( x + 3)
y + 6 = 4/5x + (3(4))/5

y + 6 = 4/5x + (12)/5
y + 6 = 4/5x + 12/5
y + 6 (-6) = 4/5x + 12/5 (-6)
y = 4/5x + 12/5 (- 30/5)


y = 4/5x - 3.6 ( y = mx + b formula)

4/5 = 0.8

y = 0.8x - 3.6

x = 1
y = 0.8(1) - 3.6
y = - 2.8

x = 2
y = 0.8(2) - 3.6
y = 1.6 - 3.6
y = -2

x = 3
y = 0.8(3) - 3.6
y = 2.4 - 3.6
y = - 1.2

x = 4
y = 0.8(4) - 3.6
y = 3.2 - 3.6
y =  - 0.4

x = 5
y = 0.8(5) - 3.6
y = 4 - 3.6
y = 0.4

etc.

graph  using the (x,y)

connect the dots

hope this helps

Ivanshal [37]3 years ago
8 0
3a. The slope is 4/5
Since the equation is in the form y-y1 = m(x-x1)
m = slope = 4/5

----------------------------------

3b. The point used is (-3,-6)
The equation y+6 = (4/5)(x+3) is the same as y-(-6) = (4/5)(x-(-3))
matching that up to y-y1 = m(x-x1) and we see (x1,y1) = (-3,-6)

----------------------------------

3c. The graph is shown in the attached images
We already have one point (-3,-6). To get another point, we use the slope. 
Slope = rise/run = 4/5
rise = 4
run = 5
Start at (-3,-6). Move up 4 units and then to the right 5 units to get to the next point (2, -2). 
Plot the two points (-3,-6) and (2,-2). Then draw a straight line through them.

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Part a:

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Part b:

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Part c:

With the help of part a:

z1z2 = 3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}

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