You need to factor the numerator and denominator...
(2x^2+4x-2x-4)/(2x^2-2x-2x+2)
(2x(x+2)-2(x+2))/(2x(x-1)-2(x-1))
((2x-2)(x+2))/((2x-2)(x-1)) so the (2x-2)s cancel out leaving
(x+2)/(x-1)
Answer:
0.4
0.3
0.04
0.2
0.06
Step-by-step explanation:
Hope this helps :)
4 is the answer to this question
9514 1404 393
Answer:
(a) x^2/16 +y^2/9 = 1
Step-by-step explanation:
The form for the equation of an ellipse centered at the origin is ...
(x/(semi-x-axis))^2 +(y/(semi-y-axis))^2 = 1
The vertex values tell you the semi-x-axis is 4 units, and the semi-y-axis is 3 units. Then you have ...
(x/4)^2 +(y/3)^2 = 1
x^2/16 +y^2/9 = 1
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In case you don't remember that form, you can try any of the points in the equations. The equation that works will quickly become apparent.
Answer:
First one - the root is in the bottom of the fraction (just like it is with trees) and she wrote it backwards. 2 to the four over three is the third root of two the power of four and not the other way around. Just change that and it's good.
Second one - he said that ln(2) = 2 and that's just not true. No way of fixing that one, he shouldn't get high as often as he does I guess.
Step-by-step explanation: