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finlep [7]
3 years ago
15

F(x)=x find k(x) = 3f(x+1)-6

Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

1

Step-by-step explanation:

plz dont ask its just a feeling

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Please answer this for me
Lady bird [3.3K]

Option A

Step-by-step explanation:

<u>RATE AS BRAINLIEST</u>

7 0
3 years ago
What is 1-2*30 answer pls
NNADVOKAT [17]

Answer:

-59

Step-by-step explanation:

5 0
3 years ago
A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major
SOVA2 [1]

the Solution

Pr(\text{STEM)}=\frac{158}{401}=0.394Pr(\text{Sophomore)}=\frac{87}{401}=0.217Pr(sophomore|Non-stem)=\frac{68}{401}=0.170Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

4 0
1 year ago
Give the slope and the y-intercept of the line y = – 6x– 4. Make sure the y-intercept is written as
jonny [76]

Answer:

Step-by-step explanation:

Slope = -6

Y-intercept (0, -4)

7 0
4 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
Nuetrik [128]

Answer:

See the attachment for formatted formulas

Step-by-step explanation:

Let X11, X12, ……,X1n  and X21 , X22……., X2n be two small independent random samples from two normal populations with means u1 and u2  and the standard deviations σ1 and σ2 respectively. If σ1= σ2 (=σ) but unknown then the unbiased pooled or combined estimate of the common variance σ2 (the term variance means that each population has the same variance) is given by

Sp2  = ((n_1-1)  s_(1^2 )+ (n_2-1) s_2^2)/(n_1+n_2-2)

Where

S12 = 1/(n_1- 1) ∑▒〖 (X_1i- X`_1)〗^2  and

S22 = 1/(n_2- 1) ∑▒〖 (X_2j- X`_2)〗^2

The test statistic

t = ((X_1`-X_2`)- (μ_1- μ_2))/(√(s_p&1/n_1 )+ 1/n_2 )

Has t distribution with v= n1 + n2 – 2 degrees of freedom.

It is used as a test statistic for testing hypotheses about the difference between two population means.

The procedure for testing hypothesis H0: μ_1- μ_2= ∆_0 in case of small independent samples when σ_1= σ_2 is as follows.

  • Formulate the null and alternative hypotheses given  σ_1= σ_2= σ unknown.

H0: μ_1- μ_2= ∆_0  against the appropriate alternative.

  • Decide the significance level α.
  • The test statistic under H0 is

t = ((X_1`-X_2`)- ∆_0  )/(√(s_p&1/n_1 )+ 1/n_2 )

Which has t distribution with v= n1 + n2 – 2 degrees of freedom.

  • Identify the critical region
  • Compute the t- value from the given data
  • Reject H0 if t falls in the critical region, accept H0 otherwise.

Download docx
6 0
3 years ago
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