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Diano4ka-milaya [45]
3 years ago
9

Evaluate 2^−1 + 2^−1.

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

1

Step-by-step explanation:

2^−1 + 2^−1

2x2^-1

1

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irina1246 [14]

Answer:

50.24m²

Step-by-step explanation:

area of circle

= 3.14 × r²

= 3.14 × 4 × 4

= 50.24

3 0
3 years ago
"the product of -6 and a number"
Irina-Kira [14]

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Answer:

-6x

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Which quadrant contains the point named by (2,-5)?
valentina_108 [34]
No idea hope you figure it out tho !!
maybe 3?
7 0
2 years ago
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Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a d
Natali5045456 [20]

<em>Complete Question:</em>

<em>Katya creates handmade sets of dolls, which is sold to craft and souvenir stores. The first set of dolls has a middle diameter of 7cm and a height of 12cm.</em>

<em>Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a dilation of the first set of dolls? </em>

<em></em>

Answer:

The new set is not a dilation of the first set

Step-by-step explanation:

Given

First Set:

Height = 12cm

Diameter = 7cm

New Set:

Height = 15.6cm

Diameter = 8.75cm

Required

Determine if the new set is a dilation of the second

To do this, we pass through the following steps:

1. Divide the height of the first set by the new set

2. Divide the diameter of the first set by the new set

3. Result in (1) and (2) must be equal if the new set is a dilation of the first set

Following the steps above:

(1)

Height\ Ratio = \frac{H_2}{H_1}

Height\ Ratio = \frac{15.6}{12}

Height\ Ratio = 1.3

(2)

Diameter\ Ratio = \frac{D_2}{D_1}

Diameter\ Ratio = \frac{8.75}{7}

Diameter\ Ratio = 1.25

(3) Make comparison

The ratio in (1) does not equal the ratio in (2)

i.e.

1.3 \neq 1.25

<em>Hence, the new set is not a dilation of the first set</em>

7 0
3 years ago
The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th
Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

A=\frac{1}{2} (b_{1} +b_{2} )h

where, h be the height of the trapezoid

b_{1} be the shorter base

b_{2} be the longer base

As per the given problem,

b_{2}=b_{1}  +6

Now,

Putting, A=72, b_{2}=b_{1}+6 and h=6 we get,

\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72

or, b_{1}+b_{1}+6 = \frac{(72)(2)}{6}

or, 2b_{1}+6 = 24

or, 2b_{1}=24-6

or, b_{1}= \frac{18}{2}

or, b_{1}=9

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

5 0
3 years ago
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