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jasenka [17]
2 years ago
7

Bbnvbncvbnvbnvbnvbnx

Mathematics
1 answer:
max2010maxim [7]2 years ago
7 0
Very nice question. glad to see you’re exploring your education with gibberish’
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Zoe's fish tank holds 27 liters of water. She uses a 3 liter container to fill the tank. How many times does she have to fill
gogolik [260]
Take 27 divide by 3 and you get 9 times!
7 0
3 years ago
Read 2 more answers
Given A(0,-4), B(0,-9), and C(-2,-5). Find the length of BC.
Ivan

Answer:

4.5

Step-by-step explanation:

B(0,-9)

C(-2,-5)

=> BC = \sqrt{(-2-0)^{2} -(-5+9)^{2} }  = 4.4721

5 0
2 years ago
Write an equation to represent the following statement. 51 5151 divided by 3 33 is k kk.
enot [183]

The equation is a quotient statement, and the equation is 51/3 = k

<h3>How to determine the equation?</h3>

The statement is given as:

51 divided by 3 is k

Represent the word "is" with "="

So, we have:

51 divided by 3 = k

Represent the word "divided" with "/"

So, we have:

51 / 3 = k

Hence, the equation is 51/3 = k

Read more about equations at:

brainly.com/question/2972832

#SPJ1

6 0
2 years ago
Is the expression below completely factored? If not, complete the factorization.
Ket [755]

Answer:

A) No, because the greatest common factor is 8y?, and the completely factored form is 8y2(4y2 - 6y + 3).

Step-by-step explanation:

Considering the expression

4y(8y3 – 12y2 + 6y)

From the elements in the parenthesis, 2 and y can still be factored out such that what will be left of each element

8y3/2y = 4y2

12y2/2y = 6y

6y/2y = 3

Hence

4y(8y3 – 12y2 + 6y) = 4y*2y(4y2 - 6y +3)

= 8y2(4y2 - 6y + 3)

6 0
3 years ago
You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8
Firlakuza [10]

Answer:

Margin of error = 4.21 ounces  

Step-by-step explanation:

According to the Question,

  • Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces

Therefore, Sample mean = 31 ounces  ,  Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces

  • Thus, Margin of error  = Z_{critical} × σ / √n  (Z_{critical} at α=.010 is 1.645)

Putting The Values, We get

1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21

Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces

8 0
2 years ago
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