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motikmotik
4 years ago
14

I need a urgent answer and explanation to this question​

Mathematics
1 answer:
lianna [129]4 years ago
6 0

Answer:

7) y = - \frac{5}{3}x

8) y = \frac{1}{2}(3x - 1)

Step-by-step explanation:

7) The equation of the straight line passing through the ordered pair (-3,5) and (3,-5) is given by

\frac{y - 5}{5 - (- 5)} = \frac{x - (- 3)}{- 3 - 3}

⇒ -3(y - 5) = 5(x + 3)

⇒ -3y + 15 = 5x + 15

⇒ 5x + 3y = 0

⇒ y = - \frac{5}{3}x (Answer)

8) The equation of the straight line passing through the ordered pair (5,7) and (11,16) is given by

\frac{y - 7}{7 - 16} = \frac{x - 5}{5 - 11}

⇒ 2(y - 7) = 3(x - 5)

⇒ 2y - 14 = 3x - 15

⇒ 3x - 2y - 1 = 0

⇒ y = \frac{1}{2}(3x - 1) (Answer)

You might be interested in
Show me how to get 3/4 of 2
Sidana [21]

Answer: 1.5

Step-by-step explanation:

3/4 simplified to 0.75

Multiply 0.75•2

To get 1.5

Or

3/4•2/1

6/4=1 1/2

Which is the same as 1.5

6 0
3 years ago
5. Which of the following is a function?
NNADVOKAT [17]

Answer:

D. (1, 1), (2, 2), (3, 3), (4,4), (5,5)

Hope this helps!

6 0
2 years ago
A metal rod is 7/8 Meters long. It will be cut into pieces that are each 1/56 meters long. How many pieces will be made from the
damaskus [11]
49 pieces because 7/8 is equivalent to 49/56. If each piece is 1/56, then there 49 of them.
6 0
3 years ago
Today onlyA desk is being sold at a 36% discount the sale price is 400 what was the price yesterday
Inessa [10]

Answer:

answer is 625

Step-by-step explanation:

400=x-36/100×x

400=64/100×x

x=400×100/64

x=625

5 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
4 years ago
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