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motikmotik
3 years ago
14

I need a urgent answer and explanation to this question​

Mathematics
1 answer:
lianna [129]3 years ago
6 0

Answer:

7) y = - \frac{5}{3}x

8) y = \frac{1}{2}(3x - 1)

Step-by-step explanation:

7) The equation of the straight line passing through the ordered pair (-3,5) and (3,-5) is given by

\frac{y - 5}{5 - (- 5)} = \frac{x - (- 3)}{- 3 - 3}

⇒ -3(y - 5) = 5(x + 3)

⇒ -3y + 15 = 5x + 15

⇒ 5x + 3y = 0

⇒ y = - \frac{5}{3}x (Answer)

8) The equation of the straight line passing through the ordered pair (5,7) and (11,16) is given by

\frac{y - 7}{7 - 16} = \frac{x - 5}{5 - 11}

⇒ 2(y - 7) = 3(x - 5)

⇒ 2y - 14 = 3x - 15

⇒ 3x - 2y - 1 = 0

⇒ y = \frac{1}{2}(3x - 1) (Answer)

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2 years ago
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AlexFokin [52]

Answer:

1.92636657×10^-3

Step-by-step explanation:

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3 years ago
Sarah Rhodes prepared one gallon of hot
makvit [3.9K]

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8 0
2 years ago
Find the equation of the line passing through point (4,2) and perpendicular to AB
Setler [38]

Answer:

a. -⅓

b. 3

c. y = 3x - 10

Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

Gradient = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 3}{7 - 1} = \frac{-2}{6} = -\frac{1}{3}

Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

m = gradient/slope

We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

y - 2 = 3x - 12

Add 2 to both sides

y = 3x - 12 + 2

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2 years ago
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3 years ago
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