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2 years ago

Whats the property in this equation 6 + 3= 3 +6

Mathematics

2 answers:

rosijanka [135]2 years ago

6 0

6 + 3= 3 + 6

commutative property of addition

hope it helps

matrenka [14]2 years ago

6 0

It is communititve property of addition which means they just switch the number but the addition sign stays the same

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What is the second step in the construction?

MrMuchimi

Answer:

To draw the perpendicular bisector of any line segment, the compass opening should be the kept constant at any value a little more than half the length of the line segment. Then the compass point should be kept on one end and arcs drawn above and below and then keeping the same compass opening the same as mentioned before, the compass point should be placed on the other end and the arcs should be drawn above and below the segment touching the previous arcs.

Thus, out of the given options, the first option best suits the next step Herberto should take.

Step-by-step explanation:

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3 years ago

use the distributive property to multiply 924 x 5. multiply 5 by all the values 924 (900+20+4). Show the product

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The product is 4,620.

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3 years ago

13.27 = t - 24.45

Alika [10]

Answer:

Step-by-step explanation:

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2 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

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2 years ago

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sattari [20]

Answer:

158.75

Step-by-step explanation:

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2 years ago

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