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3 years ago

11

Freddy is searching for a shirt and discovers that he has 12 shirts for every 6 pair of jeans. if he has 18 shirts how many pair

s of jeans does he have now?

1 answer:

Sergeu [11.5K]3 years ago

5 0

Answer:

9

Step-by-step explanation:

he has 2 shirts for 1 pair(s) pants so if you multiply 9 times 2 you get 18 and if you multiply 9 time 1 you get your answer which is 9

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The braking distance in feet of a car traveling at v miles per hour is given by d=1/20v^2 + 2.2v

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Answer: B. 500

Step-by-step explanation:

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3 years ago

Ordered pair for 3x + 5y = 2 <br><br> 9x + 11y = 14

Brums [2.3K]

Answer:

Step-by-step explanation:

-9x - 15y = -6

9x + 11y = 14

-4y = 8

y = -2

3x - 10 = 2

3x = 12

x = 4

(4, -2)

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3 years ago

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Which basic geometric term has no width, no length, and no thickness?

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Answer:

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3 years ago

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Let f(x)=−3x. The graph of f(x) is transformed into the graph of g(x) by a vertical stretch of 4 units and a translation of 4 u

Naily [24]

So the equation for these types of equations is f(x) = a(x-h)+k with h being a horizontal translation, a being a stretch/compression and k being a vertical translation. So here if you want a stretch of 4 a would be four, g(x)=4(-3x-h)+k. Also, there is a horizontal translation so it would be positive 4 into the equation. Since there is no change in the y-axis there is no vertical translation resulting in g(x) = 4(-3x-4)

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3 years ago

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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

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3 years ago

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