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3 years ago

The length of chen's office is 15.5 feet and the width is 7.8 feet.Use the formula P=2L+2w to find the perimeter of the office.

Mathematics

1 answer:

vlada-n [284]3 years ago

8 0

Answer:

p=46.6 feet

Step-by-step explanation:

formula:2l +2w. 2×15.5f. 2×7.8= 46.6 feet

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n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is

monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

$\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}$

Since the area of BPC is $\frac{3}{4}$ th part of total area, therefore area of APC is $\frac{1}{4}$ th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

$\text{Area of } \triangle BMP=\text{Area of } \triangle BMC$

$21=\text{Area of } \triangle BMC$

Area of BPC is,

$\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC$

$\text{Area of } \triangle BPC=21+21$

$\text{Area of } \triangle BPC=42$

Area of APC is,

$\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC$

$\text{Area of } \triangle APC=\frac{1}{3}\times 42$

$\text{Area of } \triangle APC=14$

Area of ABC is,

$\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC$

$\text{Area of } \triangle ABC=14+42=56$

Therefore, the area of ABC is 56 m².

5 0

3 years ago

Write an equation to model the distance between the point (2,4) and any point along the curve

zlopas [31]

Answer:

Distance D = √ [(2 - x)^2 + (3 - 4x^3)^2].

Step-by-step explanation:

Use the distance formula:

D = √[(x2 - x1)^2 + (y2 - y1)^2].

So here it is

D = √[(2 - x)^2 + (4 - y)^2] where x,y is any point on the curve.

D = √[2 - x)^2 + (4 - (4x^3 + 1))^2]

D = √ [(2 - x)^2 + (3 - 4x^3)^2]

7 0

3 years ago

Explain how the value of 7 in 327,902 will change if you move it to the tens place

Ilya [14]

In the initial number xx7,xxx; 7 is in the thousands place meaning its value is 7,000.
If it is moved to the tens place = xxx,x7x then it's value will decrease, it will become 70 only.

Every placement has its corresponding values, thus whereven the number 7 is place it is multiplied by its corresponding values (ones, tens, hundreds, etc).

5 0

3 years ago

Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)

zheka24 [161]

The magnitude of WX is $\sqrt{29}$ ⇒ c