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3 years ago

Which should Aaron use to convert a fraction to a decimal?

Mathematics

2 answers:

balu736 [363]3 years ago

6 0

Answer:

option C

Step-by-step explanation:

We are given that a fraction $8\frac{4}{9}$

We have to find that Aaron which should use to convert a fraction to a decimal

Fraction= $8\frac{4}{9}$

Fraction can be written as = $\frac{72+4}{9}=\frac{76}{9}$

76 is a numerator and 9 is denominator.

When we divide 76 by 9 then fraction convert into decimal.

$\frac{76}{9}=8.44$

Hence, option C is true.

trasher [3.6K]3 years ago

4 0

Aaron should use d..............o

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Answer:

(a) H₀: μ = 10 vs. Hₐ: μ < 10.

(b) The level of significance is 0.05.

Step-by-step explanation:

A new system is used to reduce the time customers spend waiting for teller service during peak hours at a bank.

A single mean test can be used to determine whether the waiting time has reduced.

(a)

The hypothesis to test whether the new system is effective or not is:

H₀: The mean waiting time is 10 minutes, i.e. μ = 10.

Hₐ: The mean waiting time is less than 10 minutes, i.e. μ < 10.

(b)

The information provided is:

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Compute the test statistic value as follows:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{9.5-10}{2.2/\sqrt{70}}=-1.902$

The test statistic value is t = -1.902.

Compute the p-value of the test as follows:

$p-value=P(t_{n-1}$

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The null hypothesis will be rejected if the p-value of the test is less than the significance level (α).

The p-value obtained is 0.031.

To reject the null hypothesis the value of α should be more than 0.031.

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3 years ago

Math Quiz Question! Measuring segments and Angles

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3 years ago

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

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