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3 years ago

A circle has an area of 50

Mathematics

1 answer:

nekit [7.7K]3 years ago

6 0

25 I'm guessing because half of 50 IS 25. So 25 sq m should be the answer.

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Evaluate The diagram below. Given: straight lines AD and CE. HELP ASAP‼️‼️

jenyasd209 [6]

Answer:

<CFD =62°

<AFB= 90°

Step-by-step explanation:

here you have a vertical angle, so to simply put it the answer on one side of the angle is the same answer for the opposite side of the angle. knowing this, angle <AFE is 62° and <CFD is on the opposite side making the angle the same(62°). the opposite angle of <AFB is <EFD which is 118° but both <AFB and <AFC equal 118° so you subtract 118° to <AFC degree which is 28° and you get 90°.

i hope this makes sense im not good at explaining. if anyone has a better explanation feel free to correct me.

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2 years ago

4 x tiles and 3 negative tiles = 5 x tiles and 4 positive tiles. Examine the algebra tiles. Which equation is being modeled? 4x

Andru [333]

Answer:

4x + (–3) = 5x + 4

Step-by-step explanation:

i got it right on edge. :)

9 0

2 years ago

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In a Gallup poll of randomly selected adults, 66% said that they worry about identity theft. For a group of 1013 adults, the m

Lady_Fox [76]

Answer: 669

Step-by-step explanation:

Given, In a Gallup poll of randomly selected adults, 66% said that they worry about identity theft.

i.e. The proportion of adults said that they worry about identity theft. (p) = 0.66

Sample size : n= 1013

Then , Mean for the sampling distribution of sample proportion = np

= (1013) × (0.66)

= 668.58 ≈ 669 [Round to the nearest whole number]

Hence, the mean of those who do not worry about identify theft is closest to 669 .

7 0

2 years ago

What is the surface area of this square pyramid?

OLEGan [10]

240cm2 is the answer

3 0

2 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

1 year ago

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