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gladu [14]
3 years ago
7

Suppose U={...-3,-2,-1,0,1,2,3,...} is the universal set and R={...-3,-1,1,3,...}. What is R'?

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0
Answer B!!!    .<><><><><><><><><><><><><><><>.    :)
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Find the expected value of the winnings
Bas_tet [7]

Answer:

2.65

Step-by-step explanation:

Multiply each payout by its probability, then add those products.

See the attached image.

The first column has the payouts.  The second column has the probabilities. The third column has the results of multiplying a payout by its probability.

The sum of the entries in the third column is 2.65

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3 years ago
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How would I do this? What would it be?
Vinvika [58]

50

Step-by-step explanation:

Since AE is the bisector of angle BAC,so angle BAE and Angle CAE is equal. Here Angle CAE and Angle EAC is same.

therefore,

m(Angle BAE)=m(Angle EAC)

x + 30 = 3x - 10

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or, x=20

Hence,

m(Angle EAC)=

3x - 10

=

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4 0
3 years ago
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25 POINTS PLZ HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Andrews [41]

Answer:

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7 0
4 years ago
An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p
horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

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The points A and B are located where

y=a(x+1)(x-5)=0

This gives

x=-1

y=5

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

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Thus the coordinates of B are:

B=(-1+\frac{2\sqrt{3} }{3},2)

Now this point B lies on the parabola, and therefore it must satisfy the equation  y=a(x+1)(x-5).

Thus

2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)

Therefore

a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}

\boxed{a=-0.3575}

8 0
3 years ago
Round 5.955 to the nearest tenth.
I am Lyosha [343]

Answer:

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Step-by-step explanation:

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