Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.
To find: P(100 < 152)
Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.
Solution:
Mean u = 152, std s = 18
Z score = 
The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.
P(Z=-2.89) = 0.0019
The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.
Thus the probability of 100 mm Hg blood pressure is 0.0019.
Prokaryotic - cells that don’t contain a nucleus, for example bacteria cells
Eukaryotic - cells that contain a nucleus, for example plant and animal cells
Answer:
1:C; 2:A; 3:B; 4:A; 5:C is the right answer.
Explanation:
1) rotenone
------------------C) complex I
2) CO
-------------------------A) complex IV
3) antimycin
-----------------B) complex III
4) cyanide
------------------A) complex IV
5) amytal
---------------------C) complex I
Based on the seed experiment in the Poop Lab, the seeds that are expected to sprout are the seed in the elephant poop while the seeds in the soil are not expected to sprout.
<h3>What was the Poop Lab?</h3>
The main idea of the Poop Lab is to compare the growth of seeds that have gone through the digestive system of an animal, in this case, an elephant, to a seed that has not.
The seed that had gone through the digestive system was observed to have sprouted but the seeds in the soil did not. This experiment demonstrates the role animals such as elephants play in shaping the ecosystem through seed dispersal.
The seed that passed through the digestive system of the element and then passed out into the poop received enough nutrients for growth.
However, the seed in the soil does not receive adequate nutrients.
Learn more about seed growth at: brainly.com/question/29316564
#SPJ1
The fetus does not use its lungs
