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elena-14-01-66 [18.8K]
3 years ago
6

What is 3/7 and 8/9 estimate to?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0
3/7 estimates to 0 or 1/2 and 8/9 estimates to 1.
You might be interested in
If f(x) = 2x2 + 1 and g(x) = x2 – 7, find (f – g)(x).
nadya68 [22]

Answer:  The required value is

(f-g)(x)=x^2+8.

Step-by-step explanation: The given functions are:

f(x)=2x^2+1,\\\\g(x)=x^2-7.

We are given to find the value of (f-g)(x).

We know that, if s(x) and t(x) are any two functions of a variable x, then we have

(s-t)(x)=s(x)-t(x).

Therefore, we have

(f-g)(x)\\\\=f(x)-g(x)\\\\=(2x^2+1)-(x^2-7)\\\\=2x^2+1-x^2+7\\\\=x^2+8.

Thus, the required value is

(f-g)(x)=x^2+8.

5 0
3 years ago
Solve for n <br> 3n-2=2n<br> N=
krek1111 [17]

Answer:

Hey there!

3n-2=2n

n-2=0

n=2

Let me know if this helps :)

7 0
4 years ago
Read 2 more answers
Evaluate f(x) = –x2 + 1 for x = –3. –9 4 –4 –8
Klio2033 [76]

Answer:

-63

Step-by-step explanation:

Write the problem as a mathematical expression.

f(x)=-x^2+1  for x =3-9 4-4-8

Simplify  4−4−8  to substitute in f(x)=−x^2+1

Subtract  4  from 4

0-8

Subtract  8  from 0

-8

Replace the variable  x  with  −

8  in the expression

f(-8)=-(-8)^2+1

Simplify

f(-8)=-64+1

f(-8)=-63

Answer = -63

Plz give me Brainliest if you can, hope this helps.

5 0
3 years ago
Read 2 more answers
Solve the problem down below:<br><br><br><br> ty :P
sergiy2304 [10]
The correct slope is 1!
6 0
3 years ago
Find the least number which must be added to 6203 to obtain a perfect square.
andrey2020 [161]

Answer:

79

Step-by-step explanation:

       78

         ---------

7 |       62 03 

          49

         ----------

148 |   13 03

          11 84

         -----------

            19

         -----------

78^2 = 6084.

We observe that 78^2 < 6203.

79^2 = 6241.

We observe that 79^2 > 6203.

Hence the number to be added to 6203 is 6241 - 6203 = 38.

6203 + 38 = 3241

                  = 79 * 79

                  = 79.

Therefore 38 should be added to 6203 to obtain a perfect square.

5 0
4 years ago
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