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goldenfox [79]
3 years ago
14

Evaluate f(x) = –x2 + 1 for x = –3. –9 4 –4 –8

Mathematics
2 answers:
bearhunter [10]3 years ago
6 0

Answer:

D -8

Step-by-step explanation:

Klio2033 [76]3 years ago
5 0

Answer:

-63

Step-by-step explanation:

Write the problem as a mathematical expression.

f(x)=-x^2+1  for x =3-9 4-4-8

Simplify  4−4−8  to substitute in f(x)=−x^2+1

Subtract  4  from 4

0-8

Subtract  8  from 0

-8

Replace the variable  x  with  −

8  in the expression

f(-8)=-(-8)^2+1

Simplify

f(-8)=-64+1

f(-8)=-63

Answer = -63

Plz give me Brainliest if you can, hope this helps.

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A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?
Fynjy0 [20]

Answer:

The equation showing this situation is  D=b^2-4ac=0

Step-by-step explanation:

Given : A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

To find : Which could be the equation?  

Solution :

A quadratic equation in form ax^2+bx+c=0 has a solution x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} called a quadratic formula  in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If D=b^2-4ac>0 there are two real roots.

2) If D=b^2-4ac=0 there are one real roots.

3) If D=b^2-4ac there are no real roots.

According to question,

A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

So, The equation showing this situation is  D=b^2-4ac=0

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