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Leni [432]
3 years ago
7

Which expression is equal to 5^4 ⋅ 5^8?

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0

The correct answer is A: 5^12.

alex41 [277]3 years ago
3 0

It should be A. You would keep the 5, and the exponent should be 4+8, which is 12.

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5 x 1= 5<br> 5x10=50<br> 5x100=500<br> 5x1000= 5000<br><br> What pattern do you notice ?
storchak [24]
Adds a zero each time?
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2 years ago
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Carefully review the research matrix presented below. If this is a within subjects design, how many total participants will be u
frozen [14]

Answer:

c. 45

Step-by-step explanation:

there are 15 participant in each category, and there are 3 categories, so total participants = 15 * 3

= 45

Hope this helps, and please mark me brainliest if it does!

5 0
3 years ago
Is triangle mno similar to triangle pqo explain
lesantik [10]

Answer:

Step-by-step explanation:

wha-

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2 years ago
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Triangle PQR has coordinates P(–8, 3), Q(–8, 6), and R(–3, 6). If the triangle is translated by using the rule (x, y) right-arro
amid [387]

Answer:

Step-by-step explanation: in the x's place add 4 to that number and in the y's place subtract 6 from that number:

P= -4,-3

Q= -4,0

R= 1, 0

3 0
2 years ago
Read 2 more answers
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
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