Answer:
x^-5 = x to the power of negative 5
Step-by-step explanation:
Which of these is equivalent to 1 over x to the power of 5 ?
Mathematically this is expressed as
(1/x)⁵
We have a rule when it comes to expressing power
(1/a)^b = a^-b
Hence, applying this rule to our question
(1/x)⁵ = (1/x)^5
= x^-5
This is written in words as:
x to the power of negative 5
12 tens as in 12 10's
that equals
10+10+10+10+10+10+10+10+10+10+10+10
or 12 times 10
when multiply by 10, just move decimal place on e to the right
12.0 times 10=120
the answe ris 120
Answer:
Option B. 7.6
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form 
or 
where
k is the constant of proportionality
The slope of the linear equation is the same that the constant of proportionality
In this problem we have
so
the slope is 
therefore
The constant of proportionality k is 
Answer:
a) positive direction: t < 2s & t>6s ; negative direction: 2s < t < 6s
b) 7 m
c) 71 m
Step-by-step explanation:
Given:
v(t) = 3t^2 -24t +36 [0 , 7]
Find:
a) The value of time when particle is moving in positive direction:
The change in direction of the particle can be determined by v(t) > 0
Hence,
0 < 3t^2 -24t +36
0 < t^2 - 8t + 12
0 < (t - 2)*(t - 6)
t < 2s , t > 6s
The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.
b) The displacement ds over the given interval [ 0 , 7 ]
ds = integral (v(t)).dt
ds = t^3 -12t^2 +36t
ds = 7^3 -12*7^2 +36*7
ds = 7 m
c) Total distance traveled in the interval:
Total distance= ds(0-2) + ds(2-6) + ds(6-7)
D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7
D = 2*32 - 2*0 + 7
D = 71 m
Hello,
y=-2x
Slope of the line perpendicular : ?*(-2)=-1==>?=1/2
The equation is:
y-2=1/2(x-2)
==>y=x/2-1+2
==>y=x/2+1
