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Leni [432]
3 years ago
7

Which expression is equal to 5^4 ⋅ 5^8?

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0

The correct answer is A: 5^12.

alex41 [277]3 years ago
3 0

It should be A. You would keep the 5, and the exponent should be 4+8, which is 12.

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Which equation have the same value of × as 3/5(30×-15)=72 check all that apply
DanielleElmas [232]

Answer:

Step-by-step explanation:

x=4.5

4 0
3 years ago
H(x) = 1/3x - 1 if h (15)
dalvyx [7]

Answer:

(

h

∘

f

∘

g

)

(

x

)

is known as a composite function. Here's how composite functions work:

let's say that  

x

=

1

. Your function  

g

(

x

)

=

1

3

(

x

)

now produces a  

y

output of  

1

3

, since  

g

(

1

)

=

1

3

(

1

)

. Within a composite function, the y-value of one function becomes the x-value of the next, like so:

g

(

1

)

=

1

3

⇒

f

(

1

3

)

=

17

3

⇒

h

(

17

3

)

=

17

Therefore,

(

h

∘

f

∘

g

)

(

1

)

=

17

Based on this, to find the function for  

(

h

∘

f

∘

g

)

(

x

)

(combined from right to left, by the way), simply replace  

x

in  

f

(

x

)

with the function  

g

(

x

)

, and replace  

x

in  

h

(

x

)

with the function of  

(

f

∘

g

)

(

x

)

, to get  

(

h

∘

f

∘

g

)

(

x

)

.

This, simplified, is equal to  

2

x

+

15

, and therefore  

(

h

∘

f

∘

g

)

(

1

)

=

2

(

1

)

+

15

=

17

Hope that helps!

5 0
2 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
2 years ago
Can you guys pls help me out
34kurt

Answer:

answer C

i think

hope this helps

8 0
2 years ago
Read 2 more answers
Angle A and angle B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?
mezya [45]
Ya she's right it's C bc I had the same thing on my quiz and I got it right
6 0
3 years ago
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