A function is a special type of relation where

Find the value of each variable in the parallelogram

kompoz [17]

9514 1404 393

Answer:

k = 7

m = 8

Step-by-step explanation:

The diagonals bisect each other, so each half is equal to the opposite half.

k +4 = 11 . . . . down-sloping diagonal

k = 7

__

m = 8 . . . . up-sloping diagonal

4 0

3 years ago

What is the product of 2X plus 3 and 4X squared minus 5X plus 6

Tju [1.3M]

The product of something means multiplying the terms together.

(2x+3) (4x^2-5x+6)

Secondly you need to distribute the terms to each other (Think of problems like FOIL)

2x * 4x^2 + 2x(-5x) + 2x * 6 + 3 * 4x^2 + 3(-5x) + 3 * 6

Then you must take into account that some of the numbers are negative. (minus-plus rules!)

2x * 4x^2 - 2x * 5x + 2x * 6 + 3 * 4x^2 - 3 * 5x + 3 * 6

Now is the tricky part of simplifying everything.

2x * 4x^2 = 8x^3

2x * 5x = 10x^2

2x * 6 = 12x

3 * 4x^2 = 12x^2

3 * 5x = 15x

3 * 6 = 18

8x^3 - 10x^2 + 12x + 12x^2 - 15x + 18

Then you group like terms.

8x^3 - 10x^2 + 12x^2 - 3x + 18

8x^2 + 2x^2 - 3x + 18

The trickiest part of this is distributing all of the terms within the parentheses, once you've done that, it's smooth sailing!

5 0

3 years ago

Your team wins 18 medals at a competition. The metals are gold, silver, and bronze in a ratio of 2:4:3. How many of each metal d

Anarel [89]

Answer

Find out the how many of each metal did your team win.

To prove

As given

Your team wins 18 medals at a competition.

The metals are gold, silver, and bronze in a ratio of 2:4:3.

Let us assume that x be the scalar multiple of the gold, silver and bronze medal.

Thus

Number of gold medal = 2x

Number of silver medal = 4x

Number of bronze medal = 3x

Than the equation becomes

2x + 4x + 3x = 18

9x = 18

$x = \frac{18}{9}$

x = 2

Number of gold medal = 2 × 2

= 4

Number of silver medal = 4 × 2

= 8

Number of bronze medal = 3 × 2

= 6

Therefore the number of gold medal are 4, silver medal are 8, bronze medal are 6.

3 0

3 years ago

A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0

3 years ago

Dr. David Smith lived 1/13 of his life as a child. He spent 4/39 of his life preparing for an outstanding

stich3 [128]

Answer:

40 14/25 years

Step-by-step explanation:

Well, this certainly is fun.