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3 years ago

How to write it’s inverse

Mathematics

1 answer:

seropon [69]3 years ago

8 0

F(x) = sqrt(4-x)

You can get this by switching f(x) and x and then solving for f(x).

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Find the volume of the solid. Round to the nearest tenth if necessary.

Vikki [24]

$V= \frac{4}{3} \pi r^{3} or V=4.1888 r^{3}$

r=4 $r^{3}$ =64*4.1888=268.083

V = 268.083 $mm^{3}$ so go with A.

7 0

3 years ago

Select the two values of x that are roots of this equation.

alina1380 [7]

C
;$3&;!/‘rnjakfhenfbwmdbx

4 0

3 years ago

How many grams of NH3 are required to produce 4.65 g of HF

nignag [31]

1.326 grams of NH3 are required to produce 4.65 g of HF.

Step-by-step explanation:

Balanced chemical reaction is written first to know the number of moles taking part in original reaction.

NH3 +3 F2 ⇒3 HF + NF3

Given:

mass of HF = 4.65

First the number of moles of HF in 4.65 grams is calculated by using the formula:

number of moles (n) = $\frac{mass}{atomic mass of 1 mole}$

atomic mass of HF = 20 grams/mole

putting the values in the above equation number of moles can be found.

n = $\frac{4.65}{20}$

= 0.235 moles of HF are given.

From the equation it can be said that:

1 mole of NH3 reacts to form 3 moles of HF

so, x moles of NH3 would react to form 0.235 moles of HF

$\frac{3}{1}$ = $\frac{0.235}{x}$

3x = 0.235

x = $\frac{0.235}{3}$

x = 0.078 moles of NH3 is required.

The moles are converted to mass by applying the formula:

mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)

putting the values in the formula

mass = 17 X 0.078

mass = 1.326 grams

8 0

2 years ago

What is the y-intercept of the function f(x)=4 - 5x?<br> -5<br> -4<br> 4<br> 5

Len [333]

Answer:

Step-by-step explanation: Its 4 becuase you plug in the zero like this'

f(x)=4-5(0)

f(0)=4-0

f(0)=4

So it will (0,4)

3 0

2 years ago

Simplify the expression: 2/3 divided by -4 minus (1/6 - 8/6)

guapka [62]

Answer:

Step-by-step explanation:

$\frac{2}{3} \div - 4 - ( \frac{1}{6} - \frac{8}{6} )$

$- \frac{2}{3} \times \frac{1}{4} - ( - \frac{7}{6} )$

$- \frac{1}{3} \times \frac{1}{2} + \frac{7}{6}$

$- \frac{1}{6} + \frac{7}{6}$

$\boxed{\green{= 1}}$

5 0

2 years ago