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3 years ago

12

Mathematics

1 answer:

mash [69]3 years ago

4 0

Answer:

Step-by-step explanation:

I don't think you have the right equation down, so this more of an educated guess than an actual direct answer

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-1x + 4y <4<br> how to slove this

vazorg [7]

Answer: y = 1/4x + 1

mark me as Brainliest

6 0

3 years ago

"three times a number is greater than or equal to 12 and less than 21"

Diano4ka-milaya [45]

Answer:

The required inequality is: 12 ≤ 3x < 21

Step-by-step explanation:

We are given: three times a number is greater than or equal to 12 and less than 21

We need to answer following questions:

1) The inequality translated in numerical form

Let number = x

12 ≤ 3x < 21

2) Your work solving the inequality

We need to find value of x. Divide the inequality by x

4 ≤ x < 7

3) The solution graphed on a number line

It is shown in figure attached.

4) The solution in set notation

The set notation is: Considering x belongs to natural numbers N

{∀ x|x∈N, 4 ≤ x < 7}

5) The solution in interval notation

The interval notation is: [4,7)

because we have 4 less than equal to x and x is less than 7

8 0

3 years ago

Why is it important to consider scale when graphing inequalities?

tigry1 [53]

<span>If two numbers on a graph differ by 1, without scale, the amount of inequality could vary infinitely. If the scale is 2, a difference of 1 is half the scale amount, but if the scale is 1000, the difference may be negligible. It is the scale that shows the degree to which the entries differ.</span>

4 0

3 years ago

HELP ME Using the following equation, complete the square and find the center and radius of the circle:

IrinaK [193]

Answer: $(-2,3)$ , $r=5\ \text{units}$

Step-by-step explanation:

Given

the equation is $x^2+y^2+4x-6y-12=0$

completing the square

$\Rightarrow (x^2+2\times 2\times x+4-4)+(y^2-2\times3\times y+9-9)-12=0\\\Rightarrow (x^2+2\times 2\times x+4)+(y^2-2\times3\times y+9)-12-4-9=0\\\Rightarrow (x+2)^2+(y-3)^2=25\\\Rightarrow (x+2)^2+(y-3)^2=5^2\\\Rightarrow (x-(-2))^2+(y-3)^2=5^2$

Thus, the center of the circle is $(-2,3)$ and radius is $r=5\ \text{units}$

5 0

3 years ago

30 points I'm struggling Find the equations of each line and show all of your work. (1, 5) (2, 6) (1, 1) (3, -8) (2, -3) (5, -2)

Free_Kalibri [48]

Answer:

1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b

5=1(1)+b 4=b

y=x+4

2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b

1=-9/2(1)+b b=11/2

y=-9/x+11/2

3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b

-3=1/3(2)+b -3=2/3+b

-3-2/3=b

b=-11/3

y=1/3x-11/3

4.(2,5)and (4,3) m=-1 y=-1x+b

5=-1(2)+b 5=-2+b

5+2=b

b=7

y=-1x+7

6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b

-5=1(-3)+b -5=-3+b

-5+3=b

-2=b

y=1x-2

Step-by-step explanation:

7 0

3 years ago