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Romashka [77]
3 years ago
11

NEED HELP ASAP BRAINLIEST ANSWER IF CORRECT

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0
If we need sections that are 18 ft. long from available 78 ft. long line than we will divide 78/18 =4.(3)
So we will get 4 sections that are 18 ft. long and we will have a remainder of 6 ft line not used.
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Step-by-step explanation:

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The perimeter of a rectangle is 320mm. If its length increases by 10mm and its breadth decreases by 10mm then it its area will b
wariber [46]

Answer:

The length of the original rectangle is 73.4 mm.

The breadth of the original rectangle is 86.6 mm.

Step-by-step explanation:

Given : The perimeter of a rectangle is 320 mm. If its length increases by 10 mm and its breadth decreases by 10 mm then it its area will be 32 less.

To find : Calculate the length and breadth of the original rectangle ?

Solution :

The area of the rectangle is A=L\times B

Let the length of the rectangle be 'x'

The breadth of the rectangle be 'y'

The area is A=xy

Now, length increases by 10 mm i.e. L=x+10

breadth decreases by 10 mm i.e. B=y-10

The new area is A_n=(x+10)(y-10)

According to question,

A-A_n=32

xy-(x+10)(y-10)=32 ......(1)

The perimeter of a rectangle is 320 mm.

i.e. P=2(L+B)

320=2(x+y)

x+y=160

x=160-y .....(2)

Substitute the value of y from eqn (2) in (1),

y(160-y)-(160-y+10)(y-10)=32

160y-y^2-(170-y)(y-10)=32

160y-y^2-(180y-1700-y^2)=32

160y-y^2-180y+1700+y^2=32

1700-20y=32

20y=1732

y=\frac{1732}{20}

y=86.6

Substitute in (2),

x=160-86.6

x=73.4

The length of the original rectangle is 73.4 mm.

The breadth of the original rectangle is 86.6 mm.

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