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Alex777 [14]
3 years ago
9

as a puppy, kim's dog weighs 15 ounces. as an adult, kim's dog weighs 8 pounds. how many ounces did kim's dog gain

Mathematics
2 answers:
shutvik [7]3 years ago
5 0

Answer:

113 ounces

Step-by-step explanation:

podryga [215]3 years ago
3 0
The answer is 113 ounces.

Kim's dog weighs 8 pounds. Since 1 pound is 16 ounces, Kim's dog weighs 8 × 16 ounces = 128 ounces.
As a puppy, Kim's dog <span>weighs 15 ounces.
So, the weigh that Kim's dog gained is subtraction of 128 ounces and 15 ounces:
128 ounces - 15 ounces = 113 ounces.

</span><span>Therefore, Kim's dog gained 113 ounces.</span>
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3 years ago
Mrs. Backstrom built a small wooden box for her cat. The box has a length of one and one tenth feet, a width of 1.6 feet, and a
likoan [24]

Answer:

\text{Volume of cat box}=3.52\text{ ft}^3

Step-by-step explanation:

We have been given that Mrs. Backstrom built a small wooden box for her cat. The box has a length of one and one tenth feet, a width of 1.6 feet, and a height of 2 feet. We are asked to find the volume of the box.

Let us convert one and one tenth feet into decimal.

1\frac{1}{10}=\frac{11}{10}=1.1

Since the cat box is in form of cuboid, so its volume will be equal to the product of length, width and height as:

\text{Volume of cat box}=1.10\text{ ft}\times 1.6\text{ ft}\times 2\text{ ft}

\text{Volume of cat box}=3.52\text{ ft}^3

Therefore, the volume of the cat box is 3.53 cubic feet.

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3 years ago
Is 313756 divisible by 5
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Answer:

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6 0
3 years ago
Read 2 more answers
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f(x)=\dfrac{x-9}{x^2-81}\\\\\text{The domain:}\\\\x^2-81\neq0\qquad\text{add 81 to both sides}\\\\x^2\neq81\to x\neq\pm\sqrt{81}\\\\x\neq-9\ \wedge\ x\neq9\\\\Answer:\ \boxed{\text{All real numbers except -9 and 9}}\to\boxed{x\in\mathbb{R}-\{-9,\ 9\}}

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